Question

Against the park ranger's advice, a visitor at a national park throws a stone horizontally off the edge of a 86 m high cliff and it lands a distance of 89 m from the edge of the cliff, narrowly missing a visitor below.
What was the initial horizontal velocity of the rock, in m/s? You can round your answer to the hundredth place and use g ≈ 10 m/s2.

Answer 1

The initial horizontal velocity of the rock, in m/s is 21.241 m/s.

What is projectile?

When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion. The object which follows the projectile motion.

Time taken by the stone to reach the ground is

t = √2h/g

t = √(2x 86)/9.81

t = 4.19s

The horizontal velocity is

V(x)  = Horizontal distance traveled / Time taken t

Put the values, we get

V(x) = 89 m/4.19 s

V(x) = 21.241 m/s

Thus, the horizontal velocity is 21.241 m/s

Learn more about projectile.

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