What is the acceleration aaa of the refrigerator 4 ss after the person begins pushing on it with a force of 400 NN

Physics

1 answer:

ruslelena [56]3 years ago

3 0

Answer:

2 ms^2

Explanation:

Given that the mass of the refrigerator is 200Kg

The net force acting on the refrigerator is 400N

The time takes is 4s

From Newtons's second law of motion;

F =ma

a = F/m

a = 400/200

a = 2 ms^2

This is a constant acceleration

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A 0.10 newton spring toy with a spring constant of 160 newtons per meter is compressed 0.05 meter before it is launched. When re

forsale [732]

Answer:

(1) V = 0.2 J (2) 0.05J

Explanation:

Solution

Given that:

K = 160 N/m

x = 0.05 m

Now,

(1) we solve for the initial potential energy stored

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V = 1/2 kx² = 0.5 * 160 * (0.05)²

Therefore V = 0.2 J

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By using the energy conversion, we have the following

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3 years ago

Un puente de acero de 100 m de largo a 8° C aumenta su temperatura a 24°C ¿Cuánto medirá su longitud? Valor del coeficiente de d

BartSMP [9]

La longitud final del puente de acero es 100.018 metros.

Asumamos que la dilatación térmica experimentada por el puente de acero es pequeña, de modo que podemos emplear la siguiente aproximación lineal para determinar la longitud final del puente de acero ( $L$ ), en metros:

$L = L_{o}\cdot [1+\alpha\cdot (T_{f}-T_{o})]$ (1)

Donde:

$L_{o}$ - Longitud inicial del puente, en metros.
$\alpha$ - Coeficiente de dilatación, sin unidad.
$T_{o}$ - Temperatura inicial, en grados Celsius.
$T_{f}$ - Temperatura final, en grados Celsius.

Si tenemos que $L_{o} = 100\,m$ , $\alpha = 11.5\times 10^{-6}$ , $T_{o} = 8\,^{\circ}C$ y $T_{f} = 24\,^{\circ}C$ , entonces la longitud final del puente de acero es: