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3 years ago

Which equation states Newton's second law?

Physics

1 answer:

Delicious77 [7]3 years ago

5 0

Answer:

It's actually

F=ma

Force=Mass x Acceleration

So...when we inverse it..

It becomes:

B. a= F/m

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Proper use of the friction zone makes it easier to:.

yulyashka [42]

Friction is the opposition offered to the movement of a surface on another and depends on the nature of the surfaces in contact.

<h3>What is friction?</h3>

The term friction refers to the opposition that is offered by surfaces in contact when they move over each other. The question is incomplete but I will try to help you the much I can.

Now recall that fricton only depends on the nature of the surfaces in contact. The friction is te reason when heat is provides in the moving parts of machines.

Learn more about friction: brainly.com/question/15117038

4 0

2 years ago

2) If the current in any circuit reach to infinity then its resistance becomes

sveta [45]

Given that,

Current = ∞

We know that,

Ohm's law :

Ohm's law is defined as,

The voltage of the circuit is directly proportional to the current of the circuit.

$V\propto I$

Or,

The voltage of the circuit is equal to the product of current and resistance.

In mathematically,

$V=IR$

Where, V = voltage

I = current

R = resistance

According to ohm's law,

The current in the circuit is

$I=\dfrac{V}{R}$

If the current is very less then the resistance will be infinity.

If the is reach to infinity then the resistance will be very low.

Hence, The resistance becomes very low.

3 0

4 years ago

A capacitor has a charge of 4.6 Î¼C. An E-field of 1.8 kV/mm is desired between the plates. There's no dielectric. What must be

Scrat [10]

Answer:

$A = 0.2875 m^2$

Explanation:

As we know that

$Q = 4.6 \mu C$

E = 1.8 kV/mm

now we know that electric field between the plated of capacitor is given as

$E = \frac{\sigma}{\epsilon_0}$

now we will have

$1.8 \times 10^6 = \frac{\sigma}{\epsilon_0}$

$\sigma = (1.8 \times 10^6)(8.85 \times 10^{-12})$

$\sigma = 1.6 \times 10^{-5} C/m^2$

now we have

$\sigma = \frac{Q}{A}$

now we have area of the plates of capacitor

$A = \frac{Q}{\sigma}$

$A = \frac{4.6 \times 10^{-6}}{1.6 \times 10^{-5}}$

$A = 0.2875 m^2$

5 0

3 years ago

2. A truck speeds up from a velocity of 6 m/s to 14 m/s in 4 seconds. What is the trucks acceleration? SHOW YOUR WORK

zavuch27 [327]

As it is given here

initial speed is

$v_i = 6 m/s$

After 4 seconds the final speed is

$v_f = 14 m/s$

so here we can use the formula of acceleration using kinematics

$a = \frac{v_f - v_i}{t}$

$a = \frac{14 - 6}{4}$

$a = 2 m/s^2$

so here it will accelerate at 2 m/s^2 rate.

As it is given here

initial it starts from rest

$v_i = 0 m/s$

After 2.5 seconds the final speed is

$v_f = 15 m/s$

so here we can use the formula of acceleration using kinematics

$a = \frac{v_f - v_i}{t}$

$a = \frac{15 - 0}{2.5}$

$a = 6 m/s^2$

so here it will accelerate at 6 m/s^2 rate.

i think question is not correct as in first line it is saying about a bag of trash and then in next line it is asking for the position of Jumper and bridge.

7 0

3 years ago

A space vehicle is traveling at 2980 km/h relative to Earth when the exhausted rocket motor is disengaged and sent backward. The

Strike441 [17]

Answer:

3054.4 km/h

Explanation:

Using the conservation of momentum

momentum before separation = 5M × 2980 Km/h where M represent the mass of the module while 4 M represent the mass of the motor

initial momentum = 14900 M km/h

let v be the new speed of the motor so that the

new momentum = 4Mv and the new momentum of the module = M ( v + 94 km/h )

total momentum = 4Mv + Mv + 93 M = 5 Mv + 93M

initial momentum = final momentum

14900 M km/h = 5 Mv + 93M

14900 km/h = 5v + 93

14900 - 93 = 5v

v = 2961.4 km/h

the speed of the module = 2961.4 + 93 = 3054.4 km/h

8 0

3 years ago