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cestrela7 [59]
3 years ago
14

Which equation states Newton's second law?

Physics
1 answer:
Delicious77 [7]3 years ago
5 0

Answer:

It's actually

F=ma

Force=Mass x Acceleration

So...when we inverse it..

It becomes:

B. a= F/m

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Help please
olga nikolaevna [1]

Answer:

6.8 m/ s^2

Explanation:

a = f / m

a = (67N - 6N) / 9 kg

a= 6.8 m/ s^2

8 0
3 years ago
Choose all the answers that apply. Which of the following occurs during data analysis? observations are made statistical informa
denis23 [38]

Answer:

Both of them.

Explanation:

They are both because when your analyzing data , that is what happen's.

6 0
3 years ago
The position-time equation for a certain train is
astraxan [27]

Answer:

a=4.8m/s^2

Explanation:

Hello,

In this case, since the acceleration in terms of position is defined as its second derivative:

a=\frac{d^2x(t)}{dt^2}=\frac{d^2}{dt^2}(2.9+8.8t+2.4t^2)

The purpose here is derive x(t) twice as follows:

a=\frac{d^2x(t)}{dt^2}=\frac{d}{dt}(8.8+2*2.4*t)\\ \\a=4.8m/s^2

Thus, the acceleration turns out 4.8 meters per squared seconds.

Best regards.

8 0
4 years ago
A 0.050 kg bullet strikes a 5.0 kg stationary wooden block and embeds itself in the block. The block and the bullet fly off toge
natka813 [3]

Answer: 909 m/s

Explanation:

Given

Mass of the bullet, m1 = 0.05 kg

Mass of the wooden block, m2 = 5 kg

Final velocities of the block and bullet, v = 9 m/s

Initial velocity of the bullet v1 = ? m/s

From the question, we would notice that there is just an object (i.e the bullet) moving before the collision. Also, even after the collision between the bullet and wood, the bullet and the wood would move as one object. Thus, we would use the conservation of momentum to solve

m1v1 = (m1 + m2) v, on substituting, we have

0.05 * v1 = (0.05 + 5) * 9

0.05 * v1 = 5.05 * 9

0.05 * v1 = 45.45

v1 = 45.45 / 0.05

v1 = 909 m/s

Thus, the original velocity of the bullet was 909 m/s

3 0
3 years ago
An LC circuit consists of a 3.400 capacitor and a coil with self-inductance 0.080 H and no appreciable resistance. At t = 0 the
Gnoma [55]

Answer:

Explanation:

charge on the capacitor = capacitance x potential

= 1.588 x 3.4

= 5.4 C  

Energy of capacitor  = 1 / 2 C V ² , C is capacitance , V is potential

=  .5 x 3.4 x 1.588²

= 4.29  J

If I be maximum current

energy of inductor = 1/2 L I² , L is inductance of inductor .

energy of inductance = Energy of capacitor

1/2 L I² = 4.29

I² = 107.25

I = 10.35 A

Time period of oscillation

T = 2π √ LC

=2π √ .08 X 3.4

= 3.275 s

current in the inductor will be maximum in T / 4 time

= 3.275 / 4

= .819 s.

Total energy of the system

= initial energy of the capacitor

=  4.29  J

7 0
3 years ago
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