We are required to find the cosine and tangent of 60°. Here we use an equilateral triangle whose side is 2 units, the height of the triangle by Pythagorean theorem will be √3 units, the base of the right angle triangle formed by bisection of the base will be 1 unit.
thus:
tan θ=opposite /adjacent
opposite= √3
adjacent=1
hence:
tan 60=√3/1=√3
cos θ=adjacent/ hypotenuse
adjacent=1
hypotenuse=2
thus
cos 60=1/2
Answer:
Here it is
Step-by-step explanation:
#1. 3:4
#2. 3 to 4
#3. 3/4
James can put 6 in each vase because 6 times 6 =36
Answer:
ü=2i+2j+0k
Step-by-step explanation:
The given plane 2x + 2y + 2 = 3 can also be written as:
2x+2y=3-2
2x+2y=1
The general equation for a plane is Ax+By+Cz=D and by definition the normal vector of that plane is n=Ai+Bj+Ck
Where i,j,k are the unit vectors
In order to demostrate that the vector n is normal to the plane, let R1=(a1,b1,c1) and R2=(a2,b2,c2) be two vectors that are in the plane.
If R1 ∈ Ax+By+Cz=D then Aa1+Bb1+Cc1=D
If R2 ∈ Ax+By+Cz=D then Aa2+Bb2+Cc2=D
Therefore, the vector R1R2=R2-R1=(a2-a1)i+(b2-b1)j+(c2-c1)k
You can apply the dot product. <em>If the dot product of the two vectors is zero then the vectors are normal.</em>
So, the vector which components are A,B,C is normal to the plane becase it is normal to any vector contained in the plane.
In this case:
A=2, B=2, C=0
ü=2i+2j+0k
Answer:
10
Step-by-step explanation:
anything below 5 is to the nearest tenth below