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myrzilka [38]
3 years ago
10

The length of the missing side

Mathematics
1 answer:
Rom4ik [11]3 years ago
7 0

Answer:

There is no image or context

Step-by-step explanation:

Sorry, message me back. I am sure I can asnwer your question.

You might be interested in
NEED HELP ASAP. By what percent will a fraction change if its numerator is decreased by 30% and its denominator is decreased by
joja [24]

Answer:

0.7x/0.8y = x/y * 0.7/0.8 = x/y * 0.875

So the fraction is reduced by 12.5%

5 0
3 years ago
The Tour de France is a bike race around the country of France. The bike race is a three week race that covers approximately 2,2
valentinak56 [21]

Answer:

Approximately 54.54% of race happened in the first week.

Step-by-step explanation:

We are given the following in the question:

Length of bike race in three weeks = 2,200 miles

Race covered in first week = 1,200 miles

Percentage of race covered in first week =

=\dfrac{\text{Race covered in first week}}{\text{Total length of race}}\times 100\%\\\\=\dfrac{1200}{2200}\times 100\%\\\\=54.54\%

Thus, approximately 54.54% of race happened in the first week.

4 0
2 years ago
The U.S. Bureau of Economic Statistics reports that the average annual salary in the metropolitan Boston area is $50,542. Suppos
xenn [34]

Answer:

(a) P(X > $57,000) = 0.0643

(b) P(X < $46,000) = 0.1423

(c) P(X > $40,000) = 0.0066

(d) P($45,000 < X < $54,000) = 0.6959

Step-by-step explanation:

We are given that U.S. Bureau of Economic Statistics reports that the average annual salary in the metropolitan Boston area is $50,542.

Suppose annual salaries in the metropolitan Boston area are normally distributed with a standard deviation of $4,246.

<em>Let X = annual salaries in the metropolitan Boston area</em>

SO, X ~ Normal(\mu=$50,542,\sigma^{2} = $4,246^{2})

The z-score probability distribution for normal distribution is given by;

                      Z  =  \frac{X-\mu}{\sigma }  ~ N(0,1)

where, \mu = average annual salary in the Boston area = $50,542

            \sigma = standard deviation = $4,246

(a) Probability that the worker’s annual salary is more than $57,000 is given by = P(X > $57,000)

    P(X > $57,000) = P( \frac{X-\mu}{\sigma } > \frac{57,000-50,542}{4,246 } ) = P(Z > 1.52) = 1 - P(Z \leq 1.52)

                                                                     = 1 - 0.93574 = <u>0.0643</u>

<em>The above probability is calculated by looking at the value of x = 1.52 in the z table which gave an area of 0.93574</em>.

(b) Probability that the worker’s annual salary is less than $46,000 is given by = P(X < $46,000)

    P(X < $46,000) = P( \frac{X-\mu}{\sigma } < \frac{46,000-50,542}{4,246 } ) = P(Z < -1.07) = 1 - P(Z \leq 1.07)

                                                                     = 1 - 0.85769 = <u>0.1423</u>

<em>The above probability is calculated by looking at the value of x = 1.07 in the z table which gave an area of 0.85769</em>.

(c) Probability that the worker’s annual salary is more than $40,000 is given by = P(X > $40,000)

    P(X > $40,000) = P( \frac{X-\mu}{\sigma } > \frac{40,000-50,542}{4,246 } ) = P(Z > -2.48) = P(Z < 2.48)

                                                                     = 1 - 0.99343 = <u>0.0066</u>

<em>The above probability is calculated by looking at the value of x = 2.48 in the z table which gave an area of 0.99343</em>.

(d) Probability that the worker’s annual salary is between $45,000 and $54,000 is given by = P($45,000 < X < $54,000)

    P($45,000 < X < $54,000) = P(X < $54,000) - P(X \leq $45,000)

    P(X < $54,000) = P( \frac{X-\mu}{\sigma } < \frac{54,000-50,542}{4,246 } ) = P(Z < 0.81) = 0.79103

    P(X \leq $45,000) = P( \frac{X-\mu}{\sigma } \leq \frac{45,000-50,542}{4,246 } ) = P(Z \leq -1.31) = 1 - P(Z < 1.31)

                                                                      = 1 - 0.90490 = 0.0951

<em>The above probability is calculated by looking at the value of x = 0.81 and x = 1.31 in the z table which gave an area of 0.79103 and 0.9049 respectively</em>.

Therefore, P($45,000 < X < $54,000) = 0.79103 - 0.0951 = <u>0.6959</u>

3 0
2 years ago
A rectangular photograph is surrounded by a border that is 1 inch wide on each side. The total area of the photograph and the bo
My name is Ann [436]

if 1 inch is added, you would add 2 inches to to each side of rectangle.  

You would have: W+2, and, L+2,  

Now let W+2 = x and, L+2 = y  

Total area =  x*y=M  

If 1 inch is added again, like above you add 2 inches to both sides, you would then have:

(x+2)(y+2)=M+52;  

xy+2x+2y+4=M+52;  

xy=M

2x+2y=48  

x+y=48/2=24  

Now solve :

W+2+ L+2=24  

W+L=20  

The perimeter is 2(W+L)=20*2 = 40 inches.

6 0
3 years ago
Find the length median of the trapezoid( 20 points and brainliest if answered)
Korolek [52]

Answer:

1. 36

2. 16

amdmkfefm

3 0
3 years ago
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