Answer:
16.8dm3
Explanation:
2 moles of CO gives 1 mole of N2
2 moles of CO= 2* 28= 56g
1 mole of N2 = 1* 22.4dm
56g of CO gives 22.4dm3 of N2
42.7 of CO will give> (42.7*22.4)/56
=16.8dm3
Carbon atoms have 6 neutrons.
<em>I hope this helped you out!! Happy thanksgiving! </em>
Answer:
0.74 grams of methane
Explanation:
The balanced equation of the combustion reaction of methane with oxygen is:
it is clear that 1 mol of CH₄ reacts with 2 mol of O₂.
firstly, we need to calculate the number of moles of both
for CH₄:
number of moles = mass / molar mass = (3.00 g) / (16.00 g/mol) = 0.1875 mol.
for O₂:
number of moles = mass / molar mass = (9.00 g) / (32.00 g/mol) = 0.2812 mol.
- it is clear that O₂ is the limiting reactant and methane will leftover.
using cross multiplication
1 mol of CH₄ needs → 2 mol of O₂
??? mol of CH₄ needs → 0.2812 mol of O₂
∴ the number of mol of CH₄ needed = (0.2812 * 1) / 2 = 0.1406 mol
so 0.14 mol will react and the remaining CH₄
mol of CH₄ left over = 0.1875 -0.1406 = 0.0469 mol
now we convert moles into grams
mass of CH₄ left over = no. of mol of CH₄ left over * molar mass
= 0.0469 mol * 16 g/mol = 0.7504 g
So, the right choice is 0.74 grams of methane
Protons have a positive charge. It is also important to remember that electrons have a negative charge and neutrons are neutral.
Answer:
0.0898M is the molarity of the basic solution
Explanation:
The reaction of calcium hydroxide, Ca(OH)₂ with H₃PO₄ is:
3 Ca(OH)₂ + 2 H₃PO₄ → 6H₂O + Ca₃(PO₄)₂
To solve this question we must find the moles of H3PO4 that react. With the moles and the rection we can find the moles of Ca(OH)2. Using its volume we can find its molarity:
<em>Moles H3PO4:</em>
0.0189L * (0.200mol / L) = 0.00378 moles H3PO4
<em>Moles Ca(OH)2:</em>
0.00378 moles H3PO4 * (3mol Ca(OH)2 / 2mol H3PO4) = 0.00567 moles Ca(OH)2
<em>Molarity:</em>
0.00567 moles Ca(OH)2 / 0.06315L =
<h3>0.0898M is the molarity of the basic solution</h3>
