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Fantom [35]
3 years ago
9

Poor Milhouse is hopelessly in love with Lisa. Unfortunately for Milhouse, Lisa does not feel the same way. However, Milhouse re

mains hopeful, since on any given day independently there is a 6% chance that Lisa smiles at him. (Assume a month has 30 days for this problem.) What is the probability that Milhouse goes longer than a month without a smile from Lisa
Mathematics
1 answer:
rewona [7]3 years ago
6 0

Answer:

15.6%

Step-by-step explanation:

Since each day there is a 6% chance that Lisa smiles at him then that means that each day there is a 94% chance that Lisa does not smile at him. To find the probability of Milhouse going longer than a month (30 days) without a smile from Lisa we need to multiply this percentage in decimal form for every day of the month. This can be solved easily by putting 94% to the 30th power which would be the same, but first, we need to turn it into a decimal...

94% / 100 = 0.94

0.94^{30} = 0.156

Now we can turn this decimal into a percentage by multiplying by 100

0.156 * 100 = 15.6%

Finally, we can see that the probability that Milhouse goes longer than a month without a smile from Lisa is 15.6%

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Find m∠UTS, if m∠UTV=x+15, m∠VTS=140∘, and m∠UTS=15x+15.
juin [17]

Answer:

165

Step-by-step explanation:

First, m<UTS=m<UTV+m<VTS by Angle Addition Postulate.  Then, you substitute all the values that you provided for the angles.  15x+15=x+15+140.  You then solve for x.

15x+15=x+155

14x=140

x=10

You then plug back in 10 for X in the value of m<UTS.  15(10)+15=165

8 0
3 years ago
Joe earned $2,400 this year. last year he earned $1,800. this year's earning were percentage of last year's.​
sertanlavr [38]

Answer: About 134% of last years earnings

Step-by-step explanation:

4 0
2 years ago
(a) What is the actual cost incurred in producing the 1051st and the 2191st disc? (Round your answers to the nearest cent.)
Evgen [1.6K]

This question is incomplete, the complete question is;

The total weekly cost (in dollars) incurred by Lincoln Records in pressing x compact discs is given by the following function;

C(x) = 2000 + 2x -0.0001x²  (0 ≤ x ≤ 6000) .

(a) What is the actual cost incurred in producing the 1051st and the 2191st disc? (Round your answers to the nearest cent.)

(b) What is the marginal cost when x = 1050 and 2190? (Round your answers to the nearest cent.)

Answer:

a)

Actual cost for 1051st disc is $1.79

Actual cost for 2191st disc is $1.56

b)

the marginal cost are;

C'(1050) = $1.79

C'(2190) =  $1.56

Step-by-step explanation:

Given the data in the question;

C(x) = 2000 + 2x -0.0001x²

a)

What is the actual cost incurred in producing the 1051st and the 2191st disc? (Round your answers to the nearest cent.)

Actual cost for 1051st disc will be;

⇒ C(1051) - C(1050)  

= [ 2000 + 2(1051) - 0.0001×(1051)²] - [ 2000 + 2(1050) - 0.0001×(1050)² ]

= [ 2000 + 2102 - 110.4601 ] - [ 2000 + 2100 - 110.25 =

= 3991.5399 - 3989.75

= $ 1.7899 ≈ $1.79

Actual cost for 2191st disc will be;

⇒ C(2191) - C(2190)  

= [ 2000 + 2(2191) - 0.0001×(2191)²] - [ 2000 + 2(2190) - 0.0001×(2190)² ]

= [ 2000 + 4382 - 480.0481 ] - [ 2000 + 4380 - 479.61 ]

= 5901.9519 - 5900.39

= $ 1.5619 ≈ $1.56

Therefore,

Actual cost for 1051st disc is $1.79

Actual cost for 2191st disc is $1.56

b)

What is the marginal cost when x = 1050 and 2190? (Round your answers to the nearest cent.)

Marginal cost is; C'(x) = 2 - 0.0002x

so;

C'(1050) = 2 - 0.0002(1050) = 2 - 0.21 = $1.79

C'(2190) = 2 - 0.0002(2190) = 2 - 0.438 = $1.562 ≈ $1.56

Therefore; the marginal cost is;

C'(1050) = $1.79

C'(2190) =  $1.56

3 0
2 years ago
A wallet containing 5 five dollar bills, 7 ten dollar bills, 8 twenty dollar bills is found and returned to its owner the wallet
Dominik [7]

Answer:

The probability is 2/5 that a $20 bill will be drawn from the wallet.

Step-by-step explanation:

There are 20 total bills in the wallet (5 $5, 7 $10, and 8 $20, 5+7+8=20). So if the finder and returner of the wallet was to be given one of the bills drawn from the wallet there would be an 8/20 chance the owner of the wallet would pull a 20. That's because there are 20 total bills in the wallet and 8 of them are $20.  

Simplifying 8/20... 8/20= 4/10= 2/5.

So, there is a 2/5 chance that a $20 bill will be pulled out of the wallet.

Hope this helps!

7 0
3 years ago
What is the square root of 200 - the square root of 32
Lady_Fox [76]
\sqrt{200}-\sqrt{32}=\sqrt{100*2}-\sqrt{16*2}=10\sqrt{2}-4{\sqrt{2}=6\sqrt{2}
6 0
2 years ago
Read 2 more answers
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