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klemol [59]
3 years ago
15

Ratio equivalent to 12 red beans to 5 total beans

Engineering
1 answer:
Kruka [31]3 years ago
8 0

Hello!

The answer to this question as a percentage is 240%

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Discuss the importance of dust and fluff removal from spinning mills and how it is realised in air conditioning plants
Alina [70]

Answer:

Removal of dust and fluff from spinning mill is important as it has adverse and detrimental effects on the health of the workers in these industries. Tiny and microscopic particles of various substances present in the surrounding air is transferred from one place to another and these causes various respiratory diseases and pose health hazards for the workers and make work environment unhealthy and hazardous thus affecting the over all efficiency and productivity.

Cotton dust , the major pollutant, when breathed in affetcs the lungs badly and workers experience symptoms such as respiratory problems, coughing, tightness in chest, etc.  Thus to ensure proper health of the workers spinning mills have been provided with powerful air conditioning to ensure purity of air, to maintain proper moisture levels and to ensure dust and fluff removal.

The dust and fluff laiden air is humidified, purified and then recirculated. Optimization of number of air changes/hour to clean air stream and prevent any health risk of the workers.

8 0
2 years ago
An ECG has a scalar magnitude of 1 mV on lead II and a scalar magnitude of 0.5 mV on lead III. Calculate the scalar magnitude on
s2008m [1.1K]

Answer: the scalar magnitude on lead I is 0.5 mV

Explanation:

Given that;

scalar magnitude on lead II = 1 mV

scalar magnitude on lead III = 0.5 mV

the scalar magnitude on lead I = ?

we know that;

Lead I Voltage = LA - RA -----------let this be equation 1

where LA is left arm electrode and RA is right am electrode

Also

Lead II = LL - RA

where LL is the left leg of electrode

we substitute

1 mV = LL - RA ---------------------let this be equation 2

Again

Lead III = LL - LA

we substitute

0.5 mV = LL - LA ------------------let this be equation 3

now subtract equation 3 and 2

1 mV - 0.5 mv = LL - RA - (LL - LA)

0.5 mV = LL - RA - LL + LA

0.5 mV = -RA + LA

0.5 mV = LA - RA

now taking a look at our equation 1 ( Lead I Voltage = LA - RA )

hence, Lead I Voltage = LA - RA = 0.5 mV

Therefore the scalar magnitude on lead I is 0.5 mV

3 0
3 years ago
The only function of a flywheel is to cool the engine during operation. <br> True or False?
ladessa [460]

Answer:

false

Explanation:

4 0
2 years ago
Read 2 more answers
Bananas are to be cooled from 28°C to 12°C at a rate of 1140 kg/h by a refrigerator that operates on a vapor-compression refrige
Lera25 [3.4K]

Answer:

A) COP = \frac{16.97}{9.8} = 1.731

B) P_{IN} = 0.4763

C) Second law efficiency 4.85%

exergy destruction for the cycle = 9.3237 kW

Explanation:

Given data:

T_1 = 28 degree celcius

T_2 = 12 degree celcius

\dot m = 1140 kg/h

Power to refrigerator = 9.8 kW

Cp = 3.35 kJ/kg degree C

A) Q = \dot m Cp \Delta T

        = 1140 \times 3.35\times (28-12) = 61,104 kJ/h

Q_{abs} = 61,104 kJ/h = 16.97 kJ/sec

COP = \frac{16.97}{9.8} = 1.731

b)

COP ∝ \frac{1}{P_{in}}

P_{in} wil be max when COP maximum

taking surrounding temperature T_H = 20 degree celcius

COP_{max} = \frac{T_L}{T_H- T_L} = \frac{285}{293 - 285} = 35.625

we know that

COP = \frac{heat\ obsorbed}{P_{in}}

P_{IN} = \frac{16.97}{35.62} = 0.4763

c) second law efficiency

\eta_{11} = \frac{COP_R}{(COP)_max} = \frac{1.731}{35.625} = 4.85\%

exergy destruction os given as X = W_{IN} - X_{Q2}

                                                         = 9.8 - 0.473 = 9.3237 kW

8 0
3 years ago
Two steels are being considered for the manufacture of as-forged connecting rods subjected to bending loads. One is AISI 4340 Cr
Bess [88]

Answer:

Please look at attachments carefully for the ebdurance limit of each material.

8 0
3 years ago
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