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NikAS [45]
3 years ago
7

Preheat and postheating are necessary when welding gray cast iron. * True False

Engineering
1 answer:
Zepler [3.9K]3 years ago
5 0
True will be your answer have a great day
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Write code (ReverseNames.java) that prompts the user to enter his or her full name, then prints the name in reverse order (i.e.,
yan [13]

Answer:

import java.util.Scanner;

import java.io.*;

public class Main{

    public static void main(String []args){

       

       StringBuilder reversedName = new StringBuilder();

       StringBuilder subName = new StringBuilder();

       

       Scanner myObj = new Scanner(System.in);  // Create a Scanner object

       System.out.println("Enter your full name (last name + first name)");

   

       String name = myObj.nextLine();  // Read user input

       

       for (int i = 0; i < name.length(); i++) {

           

           char currentChar = name.charAt(i);

           

           if (currentChar != ' ') {

               subName.append(currentChar);

           } else {

               reversedName.insert(0, currentChar + subName.toString());

               subName.setLength(0);

           }

       }

       String Resul = reversedName.insert(0, subName.toString()).toString();

       System.out.println("Reverse full name: " + Resul);

    }

}

Explanation:

To solve the problem we used StringBuilder, that allow us to build a string letter by letter, we are using two, one to store temporary information (subName) and the other to store the surname plus name (reversedName). After defining the variables, the program asks for the user fullname using Scanner class and it's method .nextLine (the variable 'name' will save the user input). A while loop is also used to iterate over the name, taking character by character with the method .charAt, the program will append letters in subName until it finds a space only then the content of subName will be transfer to reversedName and the content of subName will be deleted, then the program continues with the process until the end of the for loop; finally, the program places the content of subName at the beginning of reversedName, and print the result transforming the StringBuilder to a normal string.

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3 years ago
about edubrainly. it seems it takes the questions from this website, C&amp;P them, and also try's to get you to have viruses. ca
Y_Kistochka [10]

Answer:

yes

Explanation:

6 0
3 years ago
Why is Ethics an important part of engineering?
NemiM [27]

Answer:

Products created can change society, for better and for the worse

It was damaged in a fire

8 0
3 years ago
Which of the following are made up of electrical probes and connectors?
Mariulka [41]
Uhm is there a multiple choice?
6 0
3 years ago
Consider a cylinder of height h, diameter d, and wall thickness t pressurized to an internal pressure P_0 (gauge pressure, relat
Serggg [28]

Explanation:

Note: For equations refer the attached document!

The net upward pressure force per unit height p*D must be balanced by the downward tensile force per unit height 2T, a force that can also be expressed as a stress, σhoop, times area 2t. Equating and solving for σh gives:

 Eq 1

Similarly, the axial stress σaxial can be calculated by dividing the total force on the end of the can, pA=pπ(D/2)2 by the cross sectional area of the wall, πDt, giving:

Eq 2

For a flat sheet in biaxial tension, the strain in a given direction such as the ‘hoop’ tangential direction is given by the following constitutive relation - with Young’s modulus E and Poisson’s ratio ν:

 Eq 3

 

Finally, solving for unknown pressure as a function of hoop strain:

 Eq 4

 

Resistance of a conductor of length L, cross-sectional area A, and resistivity ρ is

 Eq 5

Consequently, a small differential change in ΔR/R can be expressed as

 Eq 6

Where ΔL/L is longitudinal strain ε, and ΔA/A is –2νε where ν is the Poisson’s ratio of the resistive material. Substitution and factoring out ε from the right hand side leaves

 Eq 7

Where Δρ/ρε can be considered nearly constant, and thus the parenthetical term effectively becomes a single constant, the gage factor, GF

 Eq 8

For Wheat stone bridge:

 Eq 9

Given that R1=R3=R4=Ro, and R2 (the strain gage) = Ro + ΔR, substituting into equation above:

Eq9

Substituting e with respective stress-strain relation

Eq 10

 

part b

Since, axial strain(1-2v) < hoop strain (2-v). V out axial < V out hoop.

Hence, dV hoop < dV axial.

part c  

Given data:

P = 253313 Pa

D = d + 2t = 0.09013 m

t = 65 um

GF = 2

E = 75 GPa

v = 0.33

Use the data above and compute Vout using Eq3

Eq 11  

Download docx
3 0
3 years ago
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