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2 years ago

Which of the following has the most momentum?

Physics

1 answer:

777dan777 [17]2 years ago

5 0

Answer:

0.50 kg moving at 10 m/s

Explanation:

mv = p

0.50(10) = 5.0 kg•m/s

5.0(0.50) = 2.5 kg•m/s

1(2) = 2 kg•m/s

0.40(10) = 4.0 kg•m/s

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Find the gravitational potential energy of a light that has a mass of 13.0 kg and is 4.8 m above the ground

Lynna [10]

Answer:

611.52 <---- Is your answer

Explanation:

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3 years ago

What was the speed of a space shuttle that orbited Earth at an altitude of 1482 km?

gregori [183]

Answer:

v = 7121.3 m/s

Explanation:

As we know that the centripetal force for the space shuttle is due to gravitational force of earth due to which it will rotate in circular path with constant speed

so here we will have

$\frac{mv^2}{r} = \frac{GMm}{r^2}$

here we know that

r = orbital radius = 6370 km + 1482 km

$r = 7.852 \times 10^6 m$

also we know that

$M = 5.97 \times 10^{24} kg$

now we will have

$v^2 = \frac{(6.67 \times 10^{-11})(5.97 \times 10^{24})}{7.852 \times 10^6}$

$v^2 = 5.07 \times 10^7$

$v = 7121.3 m/s$

3 0

3 years ago

Read 2 more answers

PLZ HELP ME FAST A relationship between two variables is called:

Irina18 [472]

Answer:

B- Correlation

Explanation:

6 0

2 years ago

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What linear speed must an earth satellite have to be in a circular orbit at an altitude of 159 km?

IgorLugansk [536]

Gravitational acceleration, g = GM/r^2. Additionally, for a satellite in a circular orbit, g = v^2/r

Where, G = Gravitational constant, M = Mass of earth, r = distance from the center of the earth to the satellite, v = linear speed of the satellite.

Equating the two expressions;
v^2/r = GM/r^2
v = Sqrt (GM/r);
But GM = Constant = 398600.5 km^3/sec^2
r = Altitude+Radius of the earth = 159+6371 = 6530 km

Substituting;
v = Sqrt (398600.5/6530) = 7.81 km/sec = 781 m/s

8 0

3 years ago

An insulating sphere is 8.00 cm in diameter and carries a 6.50 ÂµC charge uniformly distributed throughout its interior volume.

Kobotan [32]

Explanation:

(a) Formula to calculate the density is as follows.

$\rho = \frac{Q}{\frac{4}{3}\pi a^{3}}$