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kondor19780726 [428]

2 years ago

11

What does electrical energy transform into when used by objects in a home?

2 answers:

gavmur [86]2 years ago

7 0

Answer:

What can electrical energy be transformed into?

Electrical energy is transformed into many forms - mechanical/kinetic, sound, heat, light, and other forms of electromagnetic radiation - by everyday appliances.

Explanation:

Stells [14]2 years ago

6 0

Answer:

none of the other answers could be correct.

Explanation:

The sun nuclear energy transfers to radiant energy A fire Chemical energy transfers to thermal and radiant energy. wind turbine Kinetic motion energy transfers to electrical energy. Lightbulb Electrical energy transfers to radiant and thermal energy. Radio Electrical energy transfers to sound energy.

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Two football players with mass 75 kg and 100 kg run directly toward each other with speeds of 6 m/s and 8 m/s respectively. if t

3241004551 [841]

<u><em>heyaaaaa</em></u>

<u><em>Momentum before Pb = momentum after Pa</em></u>

Pb = 75*6 - 100*8 = -350kgm/s = Pa = (75+100)V where V is the velocity of the combined mass of the two players after the collision.

<u><em>Velocity has magnitude (speed) and direction. V = -350/175 = -2m/s </em></u>

So the two players are moving at 2m/s in the direction the 100kg player was moving before the collision.

<em><u>I arbitrarily chose the direction of the smaller player as positive so the opposite direction (of the larger player) had to be negative. </u></em>

hope it helpssss!!!!!!

6 0

2 years ago

Problem 9: Suppose you wanted to charge an initially uncharged 85 pF capacitor through a 75 MΩ resistor to 90.0% of its final vo

Bingel [31]

Answer:

$t=14.678\times 10^{-3}s$

Explanation:

Given:

Capacitance, C = 85 pF = 85 × 10⁻¹² F

Resistance, R = 75 MΩ = 75×10⁶Ω

Charge in capacitor at any time 't' is given as:

$Q=Q_o(1-e^{-\frac{t}{RC}})$

where,

Q₀ = Maximum charge = CE

E = Initial voltage

t = time

also, Q = CV

V= Final voltage = 90% of E = 0.9E

thus, we have

$C\times 0.9E=CE(1-e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}})$

or

$0.9=1-e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}}$

or

$e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}}=1-0.9=0.1$

taking log both sides, we get

$ln(e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}})=ln(0.1)=ln(\frac{1}{10})$

or

$-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}=-ln(10)$

or

$t=75\times 10^6\ \times\ 85\times 10^{-12}\times ln{10}$

or

$t=14.678\times 10^{-3}s$

3 0

3 years ago