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Anvisha [2.4K]
3 years ago
7

A researcher wants to know the effect of lighting on snacking behavior. He knows that young adults normally eat an average of =

21 grams of light snack food each day. He selects a random sample of n = 100 adults and places them in a controlled room where lighting is manipulated to mimic mid-day sunlight. Bowls of crackers are made available. Snack consumption for the sample averages M = 18.7 and s = 9.1. Does lighting impact snacking behavior?
Physics
1 answer:
horrorfan [7]3 years ago
8 0

Answer:

It does not impact snacking behavior.

Explanation:

The mean of the study was 18.7 grams, which is only 2.3 grams below the actual average grams of snacks that an adult would consume while at work, after revising this you could say that theres a significant reduction, but then the standard deviation is 9.1 this means that there are still adults that are eating more than 21 gram of snacks, so the test would result inconclusive.

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Liquids, when heated,
iren2701 [21]

Answer:

d

Explanation:

According to me answer is d but gas expand more than others

6 0
3 years ago
Mention & reasons why the ability to adapt to change is
s2008m [1.1K]

Answer:

The ability to adapt is important because :

1) It helps in the survival of human beings.

2) It brings more variation to the human kind.

3) It helps the species from getting endangered or extinct.

4) It brings transformation in the adapting kind.

Hope this helps you☺️☺️

5 0
3 years ago
Hypothetically speaking, if an object were located at the center of the Earth, the gravitational force on that object due to the
Likurg_2 [28]

Answer:

D. ) The force would be zero newtons

Explanation:

Because

If you are at the center of the earth, gravity is zero because all the mass around you is pulling "up" (every direction there is up!)

So F=mg so if g is zero F is also zero

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3 years ago
Suppose that diameters of a new species of apple have a bell-shaped distribution with a mean of 7.2cm and a standard deviation o
Svet_ta [14]

Answer:

97.5%

Explanation:

By the empirical rule (68-95-99.7),

  1. 68% of data are within <em>μ </em>- <em>σ</em> and <em>μ </em>+ <em>σ</em>
  2. 95% of data are within <em>μ </em>- 2<em>σ</em> and <em>μ </em>+ 2<em>σ</em>
  3. 99.7% of data are within <em>μ </em>- 3<em>σ</em> and <em>μ </em>+ 2<em>σ</em>

<em>σ </em> and <em>μ</em> are the standard deviation and the mean respectively.

From the question,

<em>μ</em> = 7.2 cm

<em>σ</em> = 0.38 cm

7.96 = 7.2 + (<em>n</em> × 0.38)

<em>n</em> = 2

Hence, 7.96 represents <em>μ </em>+ 2<em>σ</em>.

P(X < <em>μ </em>+ 2<em>σ</em>) = P(X < <em>μ</em>) + P(<em>μ</em> < X < <em>μ </em>+ 2<em>σ</em>)

P(X < <em>μ</em>) is the percentage less than the mean = 50%.

P(<em>μ</em> < X < <em>μ </em>+ 2<em>σ</em>) is half of P(<em>μ </em>- 2<em>σ</em> < X < <em>μ </em>+ 2<em>σ</em>) = 95% ÷ 2 = 47.5%.

Considering this, for apples that are no more than 7.96 cm,

P(X < 7.96) = P(X < 7.2) + P(7.2 < X < 7.96) = 50% + 47.5% = 97.5%

<em />

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3 years ago
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i think that the answer might be be C. one day. because it last about 4 to 6 hours

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