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nata0808 [166]
3 years ago
9

What is meant by the octet rule? What electrons are involved? How does this affect how elements bond?

Chemistry
1 answer:
FromTheMoon [43]3 years ago
4 0

Answer:

The octet rule is a chemical rule of thumb that reflects the observation that main group elements tend to bond in such a way that each atom has eight electrons in its valence shell, giving it the same electronic configuration as a noble gas

Explanation:

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1. cells

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Which source of water pollution would be the hardest to trace and control?
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Nonpoint pollution is harder to control

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Nonpoint pollution is harder to control because they include runoff from farms, golf courses, construction sites, roads. Whereas the single origin of the pollution is harder to trace.

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Which of the following chemical symbols represents the element silver?
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Silver is Ag from the latin Argentum

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The concentration of a salt solution in terms of mass by mass percentage is 20% and the mass of the solution is 500g determine t
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100 grams of solute would be present as 20% of 500 is 100
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3 years ago
It takes 49.0J to raise the temperature of an 11.5g piece of unknown metal from 13.0?C to 24.3?C. What is the specific heat for
svet-max [94.6K]

Answer:

c = 0.377 J/g.°C

c = 0.2350 J/g.°C

J = 27.3 J

Explanation:

We can calculate the heat (Q) absorbed or released by a substance using the following expression.

Q = c × m × ΔT

where,

c: specific heat

m: mass

ΔT: change in the temperature

<em>It takes 49.0J to raise the temperature of an 11.5g piece of unknown metal from 13.0°C to 24.3°C. What is the specific heat for the metal? Express your answer numerically, in J/g.°C</em>

Q = c × m × ΔT

49.0 J = c × 11.5 g × (24.3°C - 13.0°C)

c = 0.377 J/g.°C

<em>The molar heat capacity of silver is 25.35 J/mol.°C. How much energy would it take to raise the temperature of 11.5g of silver by 10.1°C? Express your answer numerically, in Joules. What is the specific heat of silver?</em>

<em />

The molar mass of silver is 107.87 g/mol. The specific heat of silver is:

\frac{25.35J}{mol.\° C} .\frac{mol}{107.87g} =0.2350J/g.\° C

Q = c × m × ΔT

Q = (0.2350 J/g.°C) × 11.5 g × 10.1°C = 27.3 J

5 0
3 years ago
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