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Svetach [21]
4 years ago
5

The Drude model uses Newton’s laws, which say that an electron in a constant electric field should experience constant accelerat

ion. What actually happens and why?
-What material parameters determine resistivity?

Which one material parameter is most responsible for the wide range of resistivities that are possible?
Physics
1 answer:
Troyanec [42]4 years ago
6 0

Answer:

Electrons are influenced by internal forces.

-On the temperature, density of electrons per unit of volume and relaxation time.

-The temperature

Explanation:

The Drude model neglects interactions between electrons and ions and with themselves. Those interactions (by which we refer as electromagnetic forces) influence in the random movement and freedom of the electron. So, they could be more restricted or could influence in conductivity more.

The deduction of the resistivity comes from the Ohm's law, which states that the Electric field in the material is proportional to the current density of electrons by a constant, which is the resistivity itself. The equation goes as follows:

\rho=\frac{m_e}{e^2n_e \tau }

Where e refers to electron (or the charge of it), τ is the relaxation time (average time between collisions), m is the mass and n is the density of charges (electrons in this case) per volume. However, experimentally resistivity is also dependent on temperature, which actually influence the relaxation time. The thermal energy influence in the behavior of the electrons, making them collide with phonons, have more randomness and reduced mean free path.

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erik [133]

The speed of both cars is the same ... 80 km per hour.

But their velocities are different, because DIRECTION is part of velocity, and their directions are different.

6 0
3 years ago
What is the frequency of a wave with a speed of 45 m/s and a wavelength of 2.5 m
mart [117]

Answer:

.05

Explanation:

wavelength/frequency = wave speed

45 = 2.5/x

x = 0.05

5 0
3 years ago
While goofing off at the ice skating rink, a student takes off her shoes and places each of them on the ice. Her friend, a hocke
sukhopar [10]

Answer:

Right shoe

Explanation:

Let the mass and velocity of incoming puck be m and v respectively.

Momentum of the colliding puck will be mv

In case of first case , the momentum of puck becomes zero so change in momentum after collision with left shoe

= mv - 0 = mv

If time duration of collision be t

rate of change of momentum

= mv / t

This is the force exerted by puck on the left shoe .

Now let us consider collision with right shoe

momentum after collision with right  shoe

- mv

change in momentum

= mv - ( - mv ) = 2mv

If time duration of collision be t

rate of change of momentum

= 2mv / t

This is the force exerted by puck on the right  shoe .

Since the force on the right shoe is more , this shoe will have greater speed

after collision.

6 0
3 years ago
A capacitor with initial charge q0 is discharged through a resistor. What multiple of the time constant τ gives the time the cap
fiasKO [112]

Answer: a) 0.13*τ ; b) 2.08*τ

Explanation: In order to explain the discharg of a capacitor through a resistor, we have to consider the following:

Q(t)=Qo* exp(-t/τ) for a lose of 1/8-th of its charge

in this case, Q(t)=7/8*Qo=7/8*exp(-t/τ)

ln(7/8)*τ=-t

then, t= -ln(7/8)*τ =0.13

For a lose of 7/8 th  of its charge , we have

Q(t)=1/7*Qo*exp(-t/τ)

t=-ln(1/8)*τ=2.08

5 0
4 years ago
Now solve the differential equation V(t)=−CRdV(t)dt for the initial conditions given in the problem introduction to find the vol
mina [271]

Answer:

V(t) = (q0/C) * e^(−t/RC )

Explanation:

If there were a battery in the circuit with EMF  E , the equation for  V(t)  would be  V(t)=E−(RC)(dV(t)/dt) . This differential equation is no longer homogeneous in  V(t)  (homogeneous means that if you multiply any solution by a constant it is still a solution). However, it can be solved simply by the substitution  Vb(t)=V(t)−E . The effect of this substitution is to eliminate the  E  term and yield an equation for  Vb(t)  that is identical to the equation you solved for  V(t) . If a battery is added, the initial condition is usually that the capacitor has zero charge at time  t=0 . The solution under these conditions will look like  V(t)=E(1−e−t/(RC)) . This solution implies that the voltage across the capacitor is zero at time  t=0  (since the capacitor was uncharged then) and rises asymptotically to  E  (with the result that current essentially stops flowing through the circuit).

8 0
3 years ago
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