1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dimaraw [331]
3 years ago
15

Turner's treadmill runs with a velocity of -1.3 m/s and speeds up at regular intervals during a half-hour workout. after 25 min,

the treadmill has a velocity of -6.5 m/s. what is the average acceleration of the treadmill during this period ?

Physics
2 answers:
sammy [17]3 years ago
8 0

Answer:

The average acceleration of the treadmill during this period is 0.00346 m/s²

Explanation:

It is given that,

Initial velocity of the treadmill, u = 1.3 m/s

After 25 minutes, the treadmill has a velocity of 6.5 m/s

Final velocity of the treadmill, v = 6.5 m/s

Time taken, t = 25 minutes = 1500 seconds

We need to find the average acceleration of the treadmill during this period. It is given by :

a=\dfrac{v-u}{t}

a=\dfrac{6.5\ m/s-1.3\ m/s}{1500\ s}

a=0.00346\ m/s^2

So, the average acceleration of the treadmill during this period is 0.00346 m/s². Hence, this is the required solution.

Travka [436]3 years ago
3 0

Given : Initial velocity = -1.3 m/s

            Final Velocity = -6.5 m/s.

            Time = 25 minutes.

To find : Average acceleration.

Solution: We are given units in meter/second (m/s).

So, we need to convert time 25 minutes in seconds.

1 minute = 60 seconds.

25 minutes = 60*25 = 1500 seconds.

Formula for average acceleration is given by,

\frac{Final \ velocity -Initial \ velocity}{Final \ time - Initial \ time }

We are not given intial time, so we can take initial time =0.

Plugging values in the above formula.

Average \ acceleration = \frac{-6.5 -(-1.3)}{1500-0}

= \frac{-5.2}{1500}

= -0.003467

or Average \ acceleration = -3.467 \times 10^{-3}\ m/s^2..


You might be interested in
A .5 kg air puck moves to the right at 3 m/s, colliding with a 1.5kg air puck that is moving to the left at 1.5 m/s.
arlik [135]

Answer:

part (a) v = 1.7 m/s towards right direction

part (b) Not an elastic collision

part (c) F = -228.6 N towards left.

Explanation:

Given,

  • Mass of the first puck = m_1\ =\ 5\ kg
  • Mass of the second puck = m_2\ =\ 3\ kg
  • initial velocity of the first puck = u_1\ =\ 3\ m/s.
  • Initial velocity of the second puck = u_2\ =\ -1.5\ m/s.

Part (a)

Pucks are stick together after the collision, therefore the final velocities of the pucks are same as v.

From the conservation of linear momentum,

m_1u_1\ +\ m_2u_2\ =\ (m_1\ +\ m_2)v\\\Rightarrow v\ =\ \dfrac{m_1u_1\ +\ m_2u_2}{m_1\ +\ m_2}\\\Rightarrow v\ =\ \dfrac{5\times 3\ -\ 1.5\times 1.5}{5\ +\ 1.5}\\\Rightarrow v\ =\ 1.7\ m/s.

Direction of the velocity is towards right due to positive velocity.

part (b)

Given,

Final velocity of the second puck = v_2\ =\ 2.31\ m/s.

Let v_1 be the final velocity of first puck after the collision.

From the conservation of linear momentum,

m_1u_1\ +\ m_2u_2\ +\ m_1v_1\ +\ m_2v_2\\\Rightarrow v_1\ =\ \dfrac{m_1u_1\ +\ m_2u_2\ -\ m_2v_2}{m_1}\\\Rightarrow v_1\ =\ \dfrac{5\times 3\ -\ 1.5\times 1.5\ -\ 1.5\times 2.31}{5}\\\Rightarrow v_1\ =\ 1.857\ m/s.

For elastic collision, the coefficient of restitution should be 1.

From the equation of the restitution,

v_1\ -\ v_2\ =\ e(u_2\ -\ u_1)\\\Rightarrow e\ =\ \dfrac{v_1\ -\ v_2}{u_2\ -\ u_1}\\\Rightarrow e\ =\ \dfrac{1.857\ -\ 2.31}{-1.5\ -\ 3}\\\Rightarrow e\ =\ 0.1\\

Therefore the collision is not elastic collision.

part (c)

Given,

Time of impact = t = 25\times 10^{-3}\ sec

we know that the impulse on an object due to a force is equal to the change in momentum of the object due to the collision,

\therefore I\ =\ \ m_1v_1\ -\ m_1u_1\\\Rightarrow F\times t\ =\ m_1(v_1\ -\ u_1)\\\Rightarrow F\ =\ \dfrac{m_1(v_1\ -\ u_1)}{t}\\\Rightarrow F\ =\ \dfrac{5\times (1.857\ -\ 3)}{25\times 10^{-3}}\\\Rightarrow F\ =\ -228.6\ N

Negative sign indicates that the force is towards in the left side of the movement of the first puck.

3 0
3 years ago
Which objects switch places in a double-replacement reaction?
nikklg [1K]
A. compounds because the reactants of a double replacement reaction do not have charges
5 0
3 years ago
Read 2 more answers
You stand on a frictionless platform that is rotating with an angular speed of 5.1 rev/s. Your arms are outstretched, and you ho
timurjin [86]

Answer:

\omega'=19.419\ rev.s^{-1}

Explanation:

Given:

angular speed of rotation of friction-less platform, \omega=5.1\ rev.s^{-1}

moment of inertia with extended weight, I=9.9\ kg.m^2

moment of inertia with contracted weight, I'=2.6\ kg.m^2

<u>Now we use the law of conservation of angular momentum:</u>

I.\omega=I'.\omega'

9.9\times 5.1=2.6\times \omega'

\omega'=19.419\ rev.s^{-1}

The angular speed becomes faster as the mass is contracted radially near to the axis of rotation.

5 0
3 years ago
What happens to an object's kinetic energy as it falls from some height?
natulia [17]

Answer:

The objects kinetic energy increases as it falls from some height.

7 0
2 years ago
how do you solve this. Recklesss randy drives down the road at 48mi/h. Looking down to send a text to his gf he takes his eyes o
Nady [450]

The whole problem here is convert units of [miles per hour]
into units of [feet per second].

(48 mile/hour) x (5,280 feet/mile) x (hour/3,600 sec) =  <em>70.4 ft/sec</em>

In 5.4 sec, the car travels  (5.4 x 70.4) =  <em>380.16 feet</em> .

That's how far back from the wreck they have to go
to find Randy's missing parts.


3 0
3 years ago
Other questions:
  • Why is the current atomic model called the "electron could model"
    13·1 answer
  • Th answer is "electric attraction is a force that can act at a distance."
    9·1 answer
  • an object is tossed upwards with the same inital velocity on the earth then on the moon . will the max
    15·1 answer
  • An air mass, shown in the image below, that forms over parts of Mexico, Texas, and Arizona will be a _______.
    5·2 answers
  • I need help with forms of energy.
    14·1 answer
  • You are working with a team to design a better electron microscope. To precisely control the beam of electrons, your team decide
    15·2 answers
  • The Pangaea theory supports the theory of plate tectonics because _____.
    12·2 answers
  • We have seen that when you generate a wave on a stretched spring, as long as the medium doesn’t change (that is, the tension and
    7·1 answer
  • How much tension must a rope withstand if it is used to accelerate a 960 kg car horizontally along a frictionless track at 1.20
    14·2 answers
  • Please help I'm stuck on this question ​
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!