The answer to this is C jellyfish i am positive 
hope this helps
        
                    
             
        
        
        
Answer:
Explanation:
The  change is as follows 
P₁ V₁ to 3P₁, V₁ ( constt volume )  --- first process 
3P₁,V₁ to 3P₁ , 5V₁ ( constt pressure ) ---- second process 
In the first process Temperature must have been increased 3 times . So if initial temperature is T₁ then final temperature will be 3 T₁
P₁V₁ = n R T₁ , n is no of moles of gas enclosed. 
nRT₁ = P₁V₁
Heat added at constant volume  = n Cv ( 3T₁ - T₁)
= n x 5/3 R X 2T₁ ( for diatomic gas Cv = 5/3 R)
= 10/3 x nRT₁
= 10/3x P₁V₁
In the second process,  Temperature must have been increased 5 times . So if initial temperature is 3T₁ then final temperature will be 15 T₁
Heat added at constant pressure in second case  
= n Cp ( 15T₁ - 3T₁)
= n x 7/3 R X 12T₁ ( For diatomic gas Cp = 7/3 R)
= 28 x nRT₁
= 28 P₁V₁
 
        
             
        
        
        
Answer:
only the weight of the ball will act on the ball
Explanation: There is no contact force on the ball. Also there is no air resistance on the ball so the friction force on the ball due to air is not shown