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Vinil7 [7]
3 years ago
11

Help me please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Chemistry
1 answer:
gulaghasi [49]3 years ago
5 0
Sunlight. Solar power!!
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A sample of nitrogen occupies 10.0 liters at 25°C what would be the new volume at 20°C? 7.9 L Ob 9.8 L 10.2 L 10.6 L
PtichkaEL [24]

Answer:

  9.4 liter

Explanation:

1) Data:

V₁ = 10.0 L

T₁ = 25°C = 25 + 273.15 K = 298.15 K

 P₁ = 98.7 Kpa

 T₂ = 20°C = 20 + 273.15 K = 293.15 K

  P₂ = 102.7 KPa

  V₂ = ?

2) Formula:

Used combined law of gases:

  PV / T = constant

  P₁V₁ / T₁ = P₂V₂ / T₂

3) Solution:

Solve the equation for V₂:

  V₂ = P₁V₁ T₂ / (P₂ T₁)

Substitute and compuite:

V₂ = P₁V₁ T₂ / (P₂ T₁)

V₂ = 98.7 KPa × 10.0 L × 293.15 K / (102.7 KPa × 298.15 K)

V₂ =  9.4 liter ← answer

You can learn more about gas law problems reading this other answer on

Explanation:

7 0
3 years ago
At STP, how many liters of oxygen are required to react completely with 3.6 liters of hydrogen to form water?
Delvig [45]
Should be 1.8L.
2 moles of hydrogen react with 1 mole of oxygen. If 2 moles of hydrogen is 3.6L, 1 mole of oxygen should be 1.8L.
7 0
3 years ago
A sample of methane gas has a volume of 10 l at a pressure of 1.5 atm and a temperature of 20 °c. what volume does the gas occup
a_sh-v [17]
We can use combined gas laws to solve for the volume of the gas
 \frac{PV}{T}
where P - pressure, V - volume , T - temperature and k - constant
\frac{P1V1}{T1} = \frac{P2V2}{T2}
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
T1 - temperature in Kelvin - 20 °C + 273 = 293 K
T2 - 40 °C + 273 = 313 K
substituting the values 
\frac{1.5 atm*10L}{293 K} =  \frac{0.9 atm*V}{313K}
V = 17.8 L
volume of the gas is 17.8 L 
7 0
3 years ago
The formula of nitrobenzene is c6h5no2. the molecular weight of this compound is __________ amu.
mafiozo [28]

The molecular weight of a given compound would simply the sum of the molar weights of each component.

 

The molar masses of the elements are:

C = 12 amu

H = 1 amu

N = 14 amu

O = 16 amu

where 1 amu = 1 g / mol

 

Since there are 6 C, 5 H, 1 N and 2 O, therefore the total molecular weight is:

molecular weight = 6 (12 amu) + 5 (1 amu) + 1 (14 amu) + 2 (16 amu)

molecular weight = 123 amu

 

Therefore the molecular weight of nitrobenzene is 123 amu or which is exactly equivalent to 123 g / mol.

4 0
3 years ago
Which incorrect aspect of Rutherford’s model was fixed by Bohr’s model?
dolphi86 [110]

Answer:

Some things that were wrong with Rutherford's model were that the orbiting electrons should give off energy and eventually spiral down into the nucleus, making the atom collapse. Bohr proposed his quantized shell model of the atom to explain how electrons can have stable orbits around the nucleus. To remedy the stability problem, Bohr modified the Rutherford model by requiring that the electrons move in orbits of fixed size and energy.

Explanation:

7 0
3 years ago
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