Question

Please help! Thanks

Answer 1

Th actual yield of the reaction is 24.86 g

We'll begin by calculating the theoretical yield of the reaction.

2Na + Cl₂ → 2NaCl

Molar mass of Na = 23 g/mol

Mass of Na from the balanced equation = 2 × 23 = 46 g

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl from the balanced = 2 × 58.5 = 117 g

From the balanced equation above,

46 g of Na reacted to produce 117 g of NaCl.

Therefore,

11.5 g of Na will react to produce = (11.5 × 117) / 46 = 29.25 g of NaCl.

Thus, the theoretical yield of NaCl is 29.25 g.

Finally, we shall determine the actual yield of NaCl.

• Percentage yield = 85%

• Theoretical yield = 29.25 g

• Actual yield =?

Actual yield = Percent yield × Theoretical yield

Actual yield = 85% × 29.25

Actual yield = 0.85 × 29.25 g

Actual yield = 24.86 g

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