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Irina-Kira [14]
3 years ago
8

Liquids have a(n)____shape and A(n)_____volume.

Chemistry
1 answer:
shusha [124]3 years ago
4 0
B. Indefinite, definite
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Which statement about scientific notation is true?
vladimir2022 [97]

Explanation:

the proper format for scientific notation the following conditions must be true

8 0
3 years ago
HHHHHEEEELLLLLPPP PPPLLEEASEEE I GIVE BRAINLIEST!!!!!!!!!
svet-max [94.6K]
1. a. FeS + 2HCl --> FeCl2 + H2S
    b. This is a double- replacement reaction. (The elements "switch partners".)

2. a.2Na + F2 --> 2NaF
    b. This is a composition/synthesis reaction. (The two reactants are combining or synthesizing to make one product.)

3. a. 2HgO --> 2Hg + O2
    b. This is a decomposition reaction. (The single reactant is breaking down or "decomposing" into multiple reactants.)

4. Hydrogen gas reacts with oxygen gas to create water in a composition/synthesis reaction.

I hope these answers will help you! If you need any explanation, ask and hopefully I can get back to you. ;)
8 0
3 years ago
What is the iupac name of this structure?
alexgriva [62]

Answer:

3–ethyl–4–methylhexane.

Explanation:

To name the above compound, do the following:

1. Determine the functional group of the compound.

2. Locate the longest continuous carbon chain. This gives the parent name of the compound.

3. Identify the substituent group attached to the compound.

4. Give the substituent the lowest possible count.

5. Combine the above to name the compound.

Now, we shall name the compound given in the question above as follow:

1. The compound contains only single bond. Therefore, the compound belong to the alkane family.

2. The longest continuous carbon chain is 6 i.e hexane.

3. The substituent group attached are:

i. Methyl, CH3.

ii. Ethyl, CH2CH3.

4. we shall name the substituents alphabetically i.e ethly will come before methyl. Therefore,

Ethyl is located at carbon 3.

Methy is located at carbon 4.

5. Therefore, the name of the compound is:

3–ethyl–4–methylhexane.

5 0
2 years ago
Determine the freezing point and boiling point of a solution that has 68.4 g of sucrose
Ymorist [56]

Answer:

Freezing T° of solution = - 3.72°C

Boiling T° of solution =  101.02°C

Explanation:

To solve this we apply colligative properties. Firstly, freezing point depression:

ΔT = Kf . m . i

ΔT = Freezing T° of pure solvent - Freezing T° of solution

Kf = Cryoscopic constant, for water is 1.86 °C/m

m = molality (moles of solute in 1kg of solvent)

i = Ions dissolved in solution

Our solute is sucrose, an organic compound so no ions are defined. i = 1.

Let's determine the moles: 68.4 g . 1mol/ 342g = 0.2 moles

molality = 0.2 mol / 0.1kg of water = 2 m

We replace data: ΔT = 1.86°C/m . 2m . 1

Freezing T° of solution = - 3.72°C

Now, we apply elevation of boiling point: ΔT = Kb . m . i

ΔT = Boiling T° of solution - Boiling T° of  pure solvent

Kf = Ebulloscopic constant, for water is 0.512 °C/m

We replace:

Boiling T° of solution - Boiling T° of pure solvent = 0.512 °C/m . 2 . 1

Boiling T° of solution = 0.512 °C/m . 2 . 1 + 100°C → 101.02°C

6 0
2 years ago
If temperature is increased , the number of collisions per second
AfilCa [17]

Answer: when the temperature is increased, the number of collisions per second increases.

Explanation:

the rate of collisions and the temperature is directly proportional. If the  energy of the gas particles is boosted by using the temperature, the chances of the particles bumping into each other due to the high energy increases, thus increasing the number of collisions. This also increases the rate of reaction. Thus when temperature is increased the number of collisions also increases.

4 0
3 years ago
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