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3 years ago

The length of a vector indicates the magnitude of the vector. true or false

Physics

2 answers:

WITCHER [35]3 years ago

4 0

Answer:

True

Explanation:

abruzzese [7]3 years ago

3 0

The length of vector denotes magnitude of vector is a TRUE statement.

Explanation:

A vector is denoted in vector diagram with the line and an arrow on the top of the line. The length of line denotes the magnitude and the arrow denoting the direction of the vector.

The vector quantity is described in both magnitude as well as the direction. The direction on vector symbol denotes the direction of arrow points.

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Suppose a car manufacturer tested its cars for front-en4 collisions by hauling them up on a crane and dropping then; from a cert

Brrunno [24]

Answer:

Generally from third equation of motion we have that

$v^2 = u^2 + 2a[s_i - s_f]$

Here v is the final speed of the car

u is the initial speed of the car which is zero

$s_i$ is the initial position of the car which is certain height H

$s_i$ is the final position of the car which is zero meters (i.e the ground)

a is the acceleration due to gravity which is g

$v^2 = 0 + 2g[H - 0]$

=> $v = \sqrt{ 2 g H}$

$H = 9.86 \ m$

Explanation:

Generally from third equation of motion we have that

$v^2 = u^2 + 2a[s_i - s_f]$

Here v is the final speed of the car

u is the initial speed of the car which is zero

$s_i$ is the initial position of the car which is certain height H

$s_i$ is the final position of the car which is zero meters (i.e the ground)

a is the acceleration due to gravity which is g

$v^2 = 0 + 2g[H - 0]$

=> $v = \sqrt{ 2 g H}$

When $v = 50 \ km/h = \frac{50 *1000}{3600} = 13.9 \ m/s$ we have that

$13.9 = \sqrt{ 2 g H}$

=> $H = \frac{13.9^2}{2 * 9.8}$

=> $H = 9.86 \ m$

6 0

3 years ago

Two identical stones are thrown from the top of a tall building. Stone 1 is thrown vertically downward with an initial speed v,

Molodets [167]

If the resistance of the Air is ignored, we can use the theory given by Galileo in which he warned that the thermal velocity of a body in free fall was given by

$v= \frac{1}{2}gt$

Where

g = Gravitational acceleration

t = time

As we can see the speed of objects in free fall is indifferent to the position that is launched (as long as the resistance of the air is ignored) or its mass.

Both bodies will end with the same thermal speed.

5 0

3 years ago

For an object in uniform circular motion, what can you say about the directions of the velocity, acceleration, and net force vec

zavuch27 [327]

Answer: b) The velocity vector is perpendicular to the acceleration vector; the acceleration vector is parallel to the net force vector.

Explanation: A change in velocity creates an acceleration. As the object rotates through the circular path it is constantly changing direction, and hence accelerating, which causes a constant force to act upon the object. This Force acts towards the center of curvature, directly toward the axis of rotation in a direction parallel to the acceleration of the body along the path. Because the object is moving perpendicular to the force, the path followed by the object is a circular one. Hence the velocity of the object is perpendicular to the acceleration.

3 0

3 years ago

Which of the following best describes the term thermal energy? Choose one: A. The energy of an object in motion due to its mass

o-na [289]

Answer:

The correct option is (d).

Explanation:

The energy a particle has because of its charge and its position relative to another particle is called thermal energy.
It is the energy that comes from heat. This is generated by the movement of the particles in an object.
Thermal energy is the energy an object or system has due to the movement of particles within.

Hence, the correct option is (d).

8 0

3 years ago

A transverse wave has a frequency of 200 Hz with a wavelength of 1.0 m. Determine the speed

Lana71 [14]

Answer:

200 m\ s Ans .....

Explanation:

Data:

f = 200 Hz

w = 1.0 m

v = ?

Formula:

v = f w

Solution:

v = ( 200)(1.0)

v = 200 m\s Ans .........

7 0

3 years ago