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3 years ago

The length of a vector indicates the magnitude of the vector. true or false

Physics

2 answers:

WITCHER [35]3 years ago

4 0

Answer:

True

Explanation:

abruzzese [7]3 years ago

3 0

The length of vector denotes magnitude of vector is a TRUE statement.

<u>Explanation: </u>

A vector is denoted in vector diagram with the line and an arrow on the top of the line. The length of line denotes the magnitude and the arrow denoting the direction of the vector.

The vector quantity is described in both magnitude as well as the direction. The direction on vector symbol denotes the direction of arrow points.

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(a) Calculate the magnitude of the gravitational force exerted on a 445-kg satellite that is a distance of 1.77 earth radii from

victus00 [196]

Answer:

a)1396.52 N

b)1396.52 N

c) $a_{satellite}= 3.13 m/sec^2$

d) $a_{earth}=2.32\times10^{-22} m/s^2$

Explanation:

The force experienced by the satelite is giveb by

$F= \frac{Gm_{satellite}m_{earth}}{r^2} \\$

m_{satellite}= 445 Kg

m_{earth}= 6×10^24 Kg

radius r= 1.77Re= 1.77×6.38×10^6 m

now putting values we get

$F= \frac{6.67\times10^{-11}(445)(6\times10^24)}{(1.77\times6.38\times10^6)^2}$

⇒F= 1396.52 N

now,

$a_{satellite}= \frac{F}{m_{satellite}}$

$a_{satellite}= \frac{1396.52}{445}$

$a_{satellite}= 3.13 m/sec^2$

also,

$a_{earth}= \frac{F}{m_{earth}}$

$a_{earth}= \frac{1396.52}{(6\times10^24)}$

$a_{earth}=2.32\times10^{-22} m/s^2$

3 0

3 years ago

An uncharged conductor has a hollow cavity inside of it. Within this cavity there is a charge of +10 µC that does not touch the

aliina [53]

Answer:

Explanation:

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so, the outer surface of the conductor should contain + 10 uC of charge and the inner surface contains -10 uC

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