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Flauer [41]
2 years ago
15

I am having trouble understanding how I got these wrong on my test. Is there something I am missing with xor?

Engineering
1 answer:
GuDViN [60]2 years ago
8 0

Answer:

  your answer is correct

Explanation:

You have the correct mapping from inputs to outputs. The only thing your teacher may disagree with is the ordering of your inputs. They might be written more conventionally as ...

 A B Y

 0 0 1

 0 1 0

 1 0 0

 1 1 1

That is, your teacher may be looking for the pattern 1001 in the last column without paying attention to what you have written in column B.

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Convection ovens operate on the principle of inducing forced convection inside the oven chamber with a fan. A small cake is to b
svetlana [45]

complete question:

attached

Answer:

2356.11 W/m^2

6100.11 W/m^2

Explanation:

Assumptions:

1. Steady-state conditions.

2. The cake is placed in a large surrounding.

3. Heat flux delivered to the cake is due to convection and radiation.  

Case 1

Since convection feature is disabled the mode of heat transfer associated with this situation is through free convection and radiation.  

q''(free) = [q''(free convection+q''(radiation) ]W/m^2

            = h_free(T_infinty - T_i) + εσ(T_air^4 - T_i^4)

            = 3 W/m^2K(180°C - 24°C) + 0.97*5.67*10^-8*[(180+273K)^4 -  

               (24+273K)^4 ]

            = 468 +1881.11

            = 2356.11 W/m^2

Case 2

Since convection feature is enabled or activated the mode of heat transfer associated with this situation is through forced convection and radiation.  

q''(free) = [q''(forced convection+q''(radiation) ]W/m^2

            = h_forced(T_infinty - T_i) + εσ(T_air^4 - T_i^4)

            = 27 W/m^2K(180°C - 24°C) + 0.97*5.67*10^-8*[(180+273K)^4 -  

               (24+273K)^4 ]

            = 4212 +1881.11

            = 6100.11 W/m^2

1. The total heat flux is is 2.58 times higher when the convection feature is activated. Therefore the cake will bake faster during this condition.  

2. The contribution of convection heat flux under natural(free) convection is very low as compared to the contribution during forced convection.  

3. The heat transfer due to radiation is same in both the cases.  

4. Only 19.9 % of the total heat flux is contributed by free convection in the first case.  

5. In the second case 69 % of the total heat flux is contributed by forced convection.  

5 0
3 years ago
This acronym is a reminder of the most common types of hazards or injuries caused by electricity.
yulyashka [42]

Answer:

BE SAFE

Explanation:

it stands for Burns, Electrocution, Shock, Arch Flash/Arc Blast, Fire, Explosions

3 0
2 years ago
How many sets of equations (V and M equations) would you need to describe shear and moment as functions of x for this beam? In o
den301095 [7]

Shear and moment as functions of x is described below .

Explanation:

1. Beam is the slender bar that carries transverse

loading; that is, the applied force are perpendicular to the bar.

2. In a beam, the internal force system consist of a shear force and

a bending moment acting on the cross section of the bar.

3. The  shear force and the bending moment usually vary continuously

along the length of the beam.

4. The internal forces give rise to two kinds of stresses on a

transverse section of a beam:

(1) normal stress that is caused by

bending moment and

(2) shear stress due to the shear force.

Knowing the distribution of the shear force and the bending

moment in a beam is essential for the computation of stresses

and deformations.

Shear- Moment Equations

The determination of the internal force system acting at a given

section of a beam : draw a free-body diagram that expose these

forces and then compute the forces using equilibrium equations.

The goal of the beam analysis -determine the shear force  V and  the bending moment  M at every cross section of the beam.

To derive the expressions for  V and M in terms of the distance x

measured along the beam. By plotting these expressions to scale,

obtain the shear force and bending moment diagrams for the

beam.

The shear force and bending moment diagrams are convenient

visual references to the internal forces in a beam; in particular,  they identify the maximum values of  V and  M

5 0
3 years ago
Assume the availability of an existing class, ICalculator, that models an integer arithmetic calculator and contains: an instanc
shtirl [24]

We connect with computers through coding, often known as computer programming.

<h3>How to code?</h3>
  • We connect with computers through coding, often understood as computer programming.
  • Coding exists similar to writing a set of instructions because it instructs a machine what to do.
  • You can instruct computers what to do or how to behave much more quickly by learning to write code.

class ICalculator {

int currentValue;

int add(int value) {

this.currentValue = currentValue + value;

return currentValue;

}

int sub(int value) {

this.currentValue = currentValue - value;

return currentValue;

}

int mul(int value) {

this.currentValue = currentValue * value;

return currentValue;

}

int div(int value) {

this.currentValue = currentValue / value;

return currentValue;

}

}

public class ICalculator2 extends ICalculator {

int negate() {

if (currentValue != 0)

this.currentValue = -currentValue;

return currentValue;

}

public static void main(String[] args) {

ICalculator2 ic = new ICalculator2();

ic.currentValue=5;

System.out.println(ic.add(2));

System.out.println(ic.sub(5));

System.out.println(ic.mul(3));

System.out.println(ic.div(3));

System.out.println(ic.negate());

}

}

To learn more about code, refer to

brainly.com/question/22654163

#SPJ4

3 0
1 year ago
It is known that the connecting rod AB exerts on the crank BCa 2.5-kN force directed down andto the left along the centerline of
monitta

Answer:

M_c = 61.6 Nm

Explanation:

Given:

F_a = 2.5 KN

Find:

Determine the moment of this force about C for the two casesshown.

Solution:

- Draw horizontal and vertical vectors at point A.

- Take moments about point C as follows:

                         M_c = F_a*( 42 / 150 ) *88

                         M_c = 2.5*( 42 / 150 ) *88

                         M_c = 61.6 Nm

- We see that the vertical component of force at point A passes through C.

Hence, its moment about C is zero.

6 0
3 years ago
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