Explanation:
there are no limits of the number of junction boxes in any particular circuit.
Answer:
a. Fraction of Atom = 2.41E-5 when T = 600K
b. Fraction of Atom = 5.03E-10 when T = 298K
Explanation:
a.
Given
T = Temperature = 600K
Qv = Energy for formation = 0.55eV/atom
To calculate the fraction of atom sites, we make use of the following formula
Nv/N = exp(-Qv/kT)
Where k = Boltzmann Constant = 8.62E-5eV/K
Nv/N = exp(-0.55/(8.62E-5 * 600))
Nv/N = 0.000024078672493307
Nv/N = 2.41E-5
b. When T = 298K
Nv/N = exp(-0.55/(8.62E-5 * 298))
Nv/N = 5.026591237904E−10
Nv/N = 5.03E-10 ----- Approximated
Answer:
It will take the steel 425.925sec to cool from 1150k to 400k
Explanation:
Detailed explanation and calculation is shown in the image
