Answer:
(a) The amount of heat transferred to the air,  is 215.5077 kJ/kg
 is 215.5077 kJ/kg
(b) The net work output,  , is 308.07 kJ/kg
, is 308.07 kJ/kg
(c) The thermal efficiency is 58.8%
(d) The Mean Effective Pressure, MEP, is 393.209 kPa
Explanation:
(a) The assumptions made are;
 = 1.005 kJ/(kg·K),
 = 1.005 kJ/(kg·K),  = 0.718 kJ/(kg·K), R = 0.287 kJ/(kg·K),
 = 0.718 kJ/(kg·K), R = 0.287 kJ/(kg·K), 
Process 1 to 2 is isentropic compression, therefore;

From;

We have;

Process 2 to 3 is reversible constant volume heating, therefore;

p₃ = 2 × p₂ = 2 × 2190.43 = 4380.86 kPa

Process 3 to 4 is isentropic expansion, therefore;




The amount of heat transferred to the air,  = 215.5077 kJ/kg
 = 215.5077 kJ/kg
(b) The net work output,  , is found as follows;
, is found as follows;



(c) The thermal efficiency is given by the relation;
 
(d) From the general gas equation, we have;

The Mean Effective Pressure, MEP, is given as follows;

The Mean Effective Pressure, MEP = 393.209 kPa.