Answer:
26 cm
Explanation:
V = Volume
R = Outer radius of the shell = 58.7 cm
r = Inner radius of the shell
g = Acceleration due to gravity = 9.81 m/s²
\rho = Density
As the shell is completely submerged
Force on shell
Weight of the shell
Equating the two equations as the forces are conserved
Inner radius of the shell is 0.561 m
The thickness of the wall is 0.587-0.561 = 0.026 m = 26 cm
C.Earth is the largest and most dense of the terrestrial planets
Answer:
The normal force N1 exerted by the floor is
The normal force N2 exerted by the wall is
The frictional force exerted by the wall is
Explanation:
From the question we are told that
The length of the ladder is
The weight of the ladder is
The distance of the ladder position on the wall from the floor is
The mass of the person is
Applying Pythagoras theorem
The length of the position the ladder on the ground from the base of the wall is
substituting values
In order the for the ladder not to shift from the ground the sum of the moment about the position of the ladder on the ground must be equal to zero this is mathematically represented as
Now the force exerted by the floor on the ladder is mathematically represented as
substituting values
Now the horizontal forces acting on the ladder are and they are in opposite direction so