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Contact [7]
3 years ago
10

Uranium-238 eventually decays into

Physics
1 answer:
GalinKa [24]3 years ago
4 0
Uranium-238 decays<span> by alpha emission </span>into<span> thorium-234, which itself </span>decays<span> by beta emission to protactinium-234, which </span>decays<span> by beta emission to </span>uranium<span>-234, and so on. The various </span>decay<span> products, (sometimes referred to as “progeny” or “daughters”) form a series starting at </span>uranium-238<span>.</span>
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2. A 200.0-kg bear grasping a vertical tree slides down at constant velocity. What is the friction force between the tree and th
Neporo4naja [7]

Answer: 1960 N

Explanation:

The bear is sliding down at constant velocity: this means that its acceleration is zero, so the net force is also zero, according to Newton's second law:

F_{net}=ma=0

There are two forces acting on the bear: its weight W, pulling downward, and the frictional force Ff, pulling upward. Therefore, the net force is given by the difference between the two forces:

F_{net}=W-F_f=0

From the previous equation, we find that the frictional force is equal to the weight of the bear:

F_f=W=mg=(200.0 kg)(9.8 m/s^2)=1960 N


8 0
3 years ago
You hear a fire truck with a certain intensity, and you are about 1 mile away. Another person hears the same fire truck with an
marin [14]

The intensity of sound is just like the force of gravity, the force between electric charges, and the intensity of light . . . they all DEcrease at the same rate that the SQUARE of the distance INcreases.

So if two people are watching or listening to the same source, and one intensity is 1/10 as intense as the other intensity, then the farther person must be  √10  times as far from the source as the nearer person is.

√10 = 3.1622 ...

So the second guy is about <em>3.16 miles</em> from the fire truck.  

4 0
3 years ago
A motorboat traveling on a straight course slows
never [62]

Answer:

2.572 m/s²

Explanation:

Convert the given initial velocity and final velocity rates to m/s:

  • 65 km/h → 18.0556 m/s
  • 35 km/h → 9.72222 m/s

The motorboat's displacement is 45 m during this time.

We are trying to find the acceleration of the boat.

We have the variables v₀, v, a, and Δx. Find the constant acceleration equation that contains all four of these variables.

  • v² = v₀² + 2aΔx

Substitute the known values into the equation.

  • (9.72222)² = (18.0556)² + 2a(45)
  • 94.52156173 = 326.0046914 + 90a
  • -231.4831296 = 90a
  • a = -2.572

The magnitude of the boat's acceleration is |-2.572| = 2.572 m/s².

3 0
3 years ago
A parallel-plate capacitor with circular plates of radius R is being discharged. The displacement current through a central circ
Dvinal [7]

Answer:

The discharging current is I_d  =  36.8 \ A

Explanation:

From the question we are told that  

     The radius of each circular plates is  R

     The displacement current is  I  = 9.2 \ A

      The radius of the central circular area is  \frac{R}{2}

The discharging current is mathematically represented as

       I_d  =  \frac{A}{k} *  I

where A is the area of each plate which is mathematically represented as

       A  =  \pi R ^2

and   k is central circular area which is mathematically represented as

     k  =  \pi [\frac{R}{2} ]^2

So  

     I_d  =  \frac{\pi R^2 }{\pi * [ \frac{R}{2}]^2 } *  I

     I_d  =  \frac{\pi R^2 }{\pi *  \frac{R^2}{4} } *  I

     I_d  =  4 *  I

substituting values

     I_d  =  4 *  9.2

     I_d  =  36.8 \ A

     

7 0
3 years ago
What is gravity?(20 points)
insens350 [35]

Answer:

The answere is A force that pulls objects toward the center of Earth

Explanation:

Hope this helpe! :)

8 0
3 years ago
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