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GrogVix [38]
3 years ago
11

How do you do question 1?

Physics
2 answers:
grin007 [14]3 years ago
8 0

Answer:

Ok, so at point 20 on the x axis you put 12 on the y-axis, then draw a line from 0, 0 to that point, this demonstrates the acceleration to 12 m/s.

Next, calculate the time he cycled for if he suckled the distance of 4800m :

4800/12 = 400 s

Put a dot at 400, 12. The time changed but the speed remained constant, line is horizontal.

For the last one, he had to decelerate at an equal speed. Since there is 100 s left of the journey at that stage, You need to draw a straight line from the previous point to 500, 0. So at time 500 he was not accelerating at all, he came to rest.

a) ?

b) -0.16 meters a second acceleration

Olenka [21]3 years ago
5 0

Answer:

DONT KNOW SORRY XD

Explanation:

BEC I AM BRAINLESS USING BRAINLY

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Answer:

F= 4788 N

Explanation:

Because the car moves with uniformly accelerated movement we apply the following formula:

vf²=v₀²+2*a*d Formula (1)

Where:  

d:displacement in meters (m)  

v₀: initial speed in m/s    

vf: final speed in m/s  

a: acceleration in m/s²

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We replace dta in the formula (1)

vf²=v₀²+2*a*d

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a= - 2.66 m/s²

Newton's second law of the car in direction  horizontal (x):

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∑F : algebraic sum of the forces in direction x-axis (N)

m : mass (kg)

a : acceleration  (m/s²)

Data

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F= 4788 N

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