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2 years ago

10

Which statement is true about the radii of Na and Na+?

1 answer:

kicyunya [14]2 years ago

5 0

Answer:

Na has a larger atomic radius than Na+.

Explanation:

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What is the value of the equilibrium constant for the reaction between Cr(s) and Cu^2+ (aq) at 25 degree C? Cr(s) + Cu^2+ (q)rig

Ludmilka [50]

Answer:

3 × 10¹⁰⁹

Explanation:

2Cr (s) → 2Cr³⁺ + 6e⁻

and,

Ec° for the above reaction = 0.74 V

also,

3Cu²⁺ (aq) + 6e⁻ → 3Cu(s)

and,

Ea° for the above reaction = 0.34 V

Now,

The cell potential, E° = 0.34 + 0.74 = 1.08

E° = $\frac{\textup{0.059}}{\textup{n}}\log k$

thus,

0.34 = $\frac{\textup{0.059}}{\textup{n}}\log k$

here, n is the number of electrons exchanged

n = 6

1.08 = $\frac{\textup{0.05921}}{\textup{6}}\log k$

or

㏒ k = 109.44

taking anti-log both sides

we get

k = 3 × 10¹⁰⁹

Hence, the answer is option (A) 3 × 10¹⁰⁹

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