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beks73 [17]
3 years ago
11

HELP!! ASAP!! WILL MARK BRAINLIEST!!!

Chemistry
2 answers:
andriy [413]3 years ago
6 0

Answer:

A

Explanation:

Lunna [17]3 years ago
5 0
The answer is A :) hope this help
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3 years ago
At what temperature (°C) will a 10.00 g sample of neon gas exert a pressure of 96.7 kPa in a
Eva8 [605]

Answer : The temperature of neon gas will be, 221.0 K

Explanation :

To calculate the temperature of neon gas we are using ideal gas equation.

PV=nRT\\\\PV=\frac{w}{M}RT

where,

P = pressure of neon gas = 96.7 kPa = 0.955 atm

Conversion used : (1 atm = 101.3 kPa)

V = volume of neon gas = 9.50 L

T = temperature of neon gas = ?

R = gas constant = 0.0821 L.atm/mole.K

w = mass of neon gas = 10.00 g

M = molar mass of neon gas = 20 g/mole

Now put all the given values in the ideal gas equation, we get:

(0.955atm)\times (9.50L)=\frac{10.00g}{20g/mole}\times (0.0821L.atm/mole.K)\times T

T=221.0K

Therefore, the temperature of neon gas will be, 221.0 K

7 0
2 years ago
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