Which organelle makes useable energy for the cell? What type of fuel did your ship need in order to work?

2 answers:

8 0

PLS I NEED HELP ASAP I DONT HAVE TIME IT ALSO DETECTS IF IT RIGHT OR WRONG. PLS I NEED HELP ASAP I DONT HAVE TIME IT ALSO PLS I NEED HELP ASAP I DONT HAVE TIME IT ALSO DETECTS IF IT RIGHT OR WRONG. DETECTS IF IT RIGHT OR WRONG. PLS I NEED HELP ASAP I DONT HAVE TIME IT ALSO DETECTS IF IT RIGHT OR WRONG. PLS I NEED HELP ASAP I DONT HAVE TIME IT ALSO DETECTS IF IT RIGHT OR WRONG. PLS I NEED HELP ASAP I DONT HAVE TIME IT ALSO DETECTS IF IT RIGHT OR WRONG. PLS I NEED HELP ASAP I DONT HAVE TIME IT ALSO DETECTS IF IT RIGHT OR WRONG. PLS I NEED HELP ASAP I DONT HAVE TIME IT ALSO DETECTS IF IT RIGHT OR WRONG.

mart [117]2 years ago

6 0

Answer:

Mitochondria -uses glucose!!

Explanation:

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A 4.305-g sample of a nonelectrolyte is dissolved in 105 g of water. the solution freezes at -1.23c. calculate the molar mass of

amid [387]

The answer is 62.00 g/mol.
Solution:
Knowing that the freezing point of water is 0°C, temperature change Δt is
Δt = 0C - (-1.23°C) = 1.23°C
Since the van 't Hoff factor i is essentially 1 for non-electrolytes dissolved in water, we calculate for the number of moles x of the compound dissolved from the equation
Δt = i Kf m
1.23°C = (1) (1.86°C kg mol-1) (x / 0.105 kg)
x = 0.069435 mol
Therefore, the molar mass of the solute is
molar mass = 4.305g / 0.069435mol = 62.00 g/mol

6 0

2 years ago

3. Hydrogen reacts with nitrogen to produce ammonia according to the equation:

lys-0071 [83]

Mass of ammonia produced : 121.38 g

<h3>Further explanation</h3>

Given

Reaction

3H₂(g) + N₂(g) ⇒ 2NH₃(g)

100g of N₂

Required

Ammonia produced

Solution

mol of N₂ :

$\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{100}{28}\\\\mol=3.57$

From the equation, mol ratio of N₂ and NH₃ = 1 : 2, so mol NH₃ :

$\tt \dfrac{2}{1}\times 3.57=7.14~moles$

mass of NH₃(MW=17 g/mol) :

$\tt mass=mol\times MW\\\\mass=7.14\times 17\\\\mass=121.38~g$

8 0

2 years ago

If you assume this reaction is driven to completion because of the large excess of one ion, what is the concentration of [Fe(SCN

viktelen [127]

Answer : The concentration of $[Fe(SCN)]^{2+}$ is, $4.32\times 10^{-4}M$

Explanation :

When we assume this reaction is driven to completion because of the large excess of one ion then we are assuming limiting reagent is $SCN^-$ and $Fe^{3+}$ is excess reagent.