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sweet [91]
2 years ago
8

In the graphic, 195 represents the _______.

Chemistry
1 answer:
Marrrta [24]2 years ago
5 0

Answer:

ITS ANSWER IS

OPTION B. ATOMIC NUMBER

HI HAVE A NICE DAY

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Assess two situations in which it is important to question scientific issues in the media.
vlabodo [156]

Answer:

Claims based on vague statements and statements from non-experts.

Explanation:

4 0
2 years ago
Which of the following state of matter has the modt space between the particles​
lesya [120]

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(A)Flammability

8 0
2 years ago
How many grams of nitric acid HNO₃, are required to neutralize (completely react with) 4.30 grams of Ca(OH)2 according to the ac
Brrunno [24]

Answer:

7.32g of HNO3 are required.

Explanation:

1st) From the balanced reaction we know that 2 moles of HNO3 react with 1 mole of Ca(OH)2 to produce 2 moles of H2O and 1 mole of Ca(NO3)2.

From this, we find that the relation between HNO3 and Ca(OH)2 is that 2 moles of HNO3 react with 1 mole of Ca(OH)2.

2nd) This is the order of the relations that we have to use in the equation to calculate the grams of nitric acid:

• starting with the 4.30 grams of Ca(OH)2.

,

• using the molar mass of Ca(OH)2 (74g/mol).

,

• relation of the 2 moles of HNO3 that react with 1 mole of Ca(OH)2 .

,

• using the molar mass of HNO3 (63.02g/mol).

4.30g\text{ Ca\lparen OH\rparen}_2*\frac{1\text{ mol Ca\lparen OH\rparen}_2}{74g\text{ Ca\lparen OH\rparen}_2}*\frac{2\text{ moles HNO}_3}{1\text{ mole Ca\lparen OH\rparen}_2}*\frac{63.02g\text{ HNO}_3}{1\text{ mole HNO}_3}=7.32g\text{ HNO}_3

So, 7.32g of HNO3 are required.

4 0
1 year ago
Can someone help me with this please
dusya [7]
Boiling water: It starts bubbling and it becomes hot
Baking Cake: The cake becomes soft and not liquid
Burning Wood: The wood burns and turns into ash
Painting Door: The color changes and the wood numbs slightly

Hope this helps!
STSN
6 0
3 years ago
Read 2 more answers
Equivalencia de un año luz en SI
Aleksandr [31]
Hi uhh i've never really typed in Spanish but here I go! :)

 Un ano luz es equivalente a 9.467 PM
4 0
3 years ago
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