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pickupchik [31]
3 years ago
11

To push a heavy box up a ramp into a moving van, what could be used to decrease the force of friction?

Physics
2 answers:
inn [45]3 years ago
7 0

Answer:

B. Put a lubricant between the ramp and the box

D. Place rollers or wheels on the bottom of the box

GuDViN [60]3 years ago
3 0

Answer:

D.Place rollers or wheels on the bottom of the box.

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onsider what happens when you jump up in the air. Which of the following is the most accurate statement?A) Since the ground is s
Likurg_2 [28]

Answer: D

Explanation: it seem right to me I really don't know if this right but I hope this helps

5 0
4 years ago
A car travels 554 miles south in 10.4 hours . what is the velocity of the car ? show all steps
kirill115 [55]

Answer:

<h3>The answer is 53.27 mi/hr</h3>

Explanation:

To find the velocity covered by the car we use the formula

v =  \frac{d}{t}  \\

where

d is the distance

t is the time

From the question

d = 554 miles

t = 10.4 hrs

We have

d =  \frac{554}{10.4}  \\  = 53.2692307...

We have the final answer as

<h3>53.27 mi/hr</h3>

Hope this helps you

4 0
4 years ago
Which statement best describes how today’s scientific community views light?
Anna11 [10]

Light behaves like both waves and particles.

4 0
4 years ago
Read 2 more answers
Excellent human jumpers can leap straight up to a
Shkiper50 [21]

The speed that the person needs to leave the ground will be 4.32m/s

From the question given,

Height = 95cm

Since the person leave the ground v = 0m/s

acceleration due to gravity g = 9.8m/s²

Using the equation of motion

v² = u² + 2as

a = -g (upward motion)

s = h (distance changes to height)

The equation will become:

0² = u² - 2gh

0² = u² - 2(9.8)(0.95)

u² = 18.62

u = √18.62

u = 4.32

Hence the speed that the person needs to leave the ground will be 4.32m/s

Learn more here: brainly.com/question/20352766

8 0
2 years ago
a wave having a wavelength of 4.7 meters and an amplitude of 2.5 meters travels a distance of 28 meters in 7 seconds. determine
Aleksandr [31]

Answer:

<h2>T(Period) = 1.33s</h2><h2>f(Frequency) = 0.75Hz (cycles/second)</h2>

Explanation:

<h2>Given:</h2><h2 /><h2>λ = 4.0m</h2><h2>Amplitude = 25m</h2><h2>d = 24m</h2><h2>s = 8.0s</h2><h2 /><h2>Required:</h2><h2>f = ?</h2><h2>T = ?</h2><h2 /><h2>Analysis:</h2><h2>v = λf</h2><h2>f =N/t</h2><h2>T = 1/f</h2><h2 /><h2>v = d/t</h2><h2 /><h2>Solve:</h2><h2>v = d/t = 24/8.0 → v = 3.0m/s</h2><h2>v =λf → f = v/λ = 3.0/4.0 → f = 0.75Hz</h2><h2>T = 1/f = 1/0.75 → T = 1.33s</h2><h2 /><h2>Hopes this helps. Mark as brainlest plz!</h2>
4 0
3 years ago
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