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iris [78.8K]
2 years ago
5

The seatbelt across your chest should have about ________ fist width of slack.

Physics
1 answer:
maw [93]2 years ago
7 0
It should have 1 or even less. Modern seat-belts have almost no slack when the sensors detect that the seat-belt has been rapidly expanded. This is done so to hold you in place and prevent you from slamming against the seat-belt if you have a collision at high speeds.
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What are four drawbacks to using fossil fuels in Alberta thermal power stations?
puteri [66]

Answer:

Fossil fuels have been used for centuries to generate power, but there are many disadvantages associated with their use:

Fossil fuels pollute the environment.

Fossil fuels are non-renewable and unsustainable.

Drilling for fossil fuels is a dangerous process.

Explanation:

can you help me please? brainly.com/question/21745542

6 0
3 years ago
The length of a wooden rod is 25.5 cm. What is this length in:<br>(a) millimetres?<br>(b) metres?​
larisa86 [58]

Answer:

(a)255mm \\ (b)0.255m

Explanation:

(a)1cm = 10mm \\ 25.5cm = x

Cross multiply

1x = 25.5 \times 10 \\ x = 255mm

(b)100cm = 1m \\ 25.5cm = x

cross multiply

100x = 25.5 \\  \frac{100x}{100}  =  \frac{25.5}{100}  \\ x = 0.255m

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4 0
3 years ago
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HELP!! An illustration of a pendulum at 3 positions of a pendulum. The equilibrium position is labeled B. The other two position
zmey [24]

Answer

the answer is A and c

Explanation:

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5 0
2 years ago
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Three polarizing filters are shown in the figure below. The alignment of each filterâs transmission axis is shown, as measured f
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5 0
2 years ago
A 16.0 kg child on roller skates, initially at rest, rolls 2.0 m down an incline at an angle of 20.0° with the horizontal. If th
enyata [817]

The kinetic energy of the child at the bottom of the incline is 106.62 J.

The given parameters:

  • <em>Mass of the child, m = 16 kg</em>
  • <em>Length of the incline, L = 2 m</em>
  • <em>Angle of inclination, θ = 20⁰</em>

The vertical height of fall of the child from the top of the incline is calculated as;

sin(20) = \frac{h}{2} \\\\h = 2 \times sin(20)\\\\h = 0.68 \ m

The gravitational potential energy of the child at the top of the incline is calculated as;

P.E = mgh\\\\P.E = 16 \times 9.8 \times 0.68\\\\P.E = 106.62 \ J

Thus, based on the principle of conservation of mechanical energy, the kinetic energy of the child at the bottom of the incline is 106.62 J since no energy is lost to friction.

Learn more about conservation of mechanical energy here: brainly.com/question/332163

7 0
2 years ago
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