Answer:
<u><em>note:</em></u>
<u><em>solution is attached in word form due to error in mathematical equation. furthermore i also attach Screenshot of solution in word due to different version of MS Office please find the attachment</em></u>
The air flow necessary to remain at the lower explosive level is 4515. 04cfm
<h3>How to solve for the rate of air flow</h3>
First we have to find the rate of emission. This is solved as
2pints/1.5 x 1min
= 2/1.5x60
We have the following details
SG = 0.71
LEL = 1.9%
B = 10% = 0.1 a constant
The molecular weight is given as 74.12
Then we would have Q as
403*100*0.2222 / 74.12 * 0.71 * 0.1
= Q = 4515. 04
Hence we can conclude that the air flow necessary to remain at the lower explosive level is 4515. 04cfm
Read more on the rate of air flow on brainly.com/question/13289839
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Answer:
a) 244,140,625 different ways
b) 390,625 different ways
Explanation:
a) If there are 5 ways to place a chip on each location, and there are 12 locations overall, we have:
5^12 ways of placing them
This would mean a total of 244,140,625 different ways
b) If five chips are of the same type, we can first find how many ways we can place chips on the remaining 7 locations:
5^7 = 78,125
Next we can multiply this by the number of ways the next 5 chips could be the same:
78,125 * 5 = 390,625 different ways
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