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sleet_krkn [62]
3 years ago
8

Fast plz-The mirror check may involve ______________.

Engineering
1 answer:
barxatty [35]3 years ago
6 0

Answer:

Realigning the mirror

Explanation:

mirrors should be aligned to minimize blind spots, not look at the tires.

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An internal combustion engine in which air is compressed to a high enough pressure and temperature that combustion occurs when f
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Answer:

Spark

Explanation

The spark plug fires igniting the fuel. In diesel trucks the air is compressed until ignition.

3 0
2 years ago
How can a standard curve be used to determine the concentration of a solution?
exis [7]

Standard curves are used to determine the concentration of substances. They are obtained by relating a measured quantity to the concentration of the substance of interest in "known" samples, i.e. Standards of known concentration. These standards provide a reference to determine unknown concentrations.

7 0
4 years ago
Where the inertial/ convective term is dominant?
const2013 [10]

Answer:

The inertial or convection term is dominant in the laminar regime. Generally, the laminar flow occur when the fluid is viscous and when it is moving very slowly.

Laminar regime is characterized by the low momentum convection and the high momentum diffusion.

The laminar regime flow is basically occur at the low velocities. When the reynolds number is less than 1, then the fluid exhibited stokes. Then, the viscous force in the fluid deaminate the convection or inertial forces.  

6 0
3 years ago
Consider a Carnot refrigeration cycle executed in a closed system in the saturated liquid-vapor mixture region using 0.96 kg of
Eduardwww [97]

Answer:

P_m_i_n= 356.9 KPa

Explanation:

Coefficient of performance (COP) of refrigeration cycle is given by:

COP=\frac{1}{\frac{T_H}{T_L}-1 }

We are given:

T_H=1.2T_L

COP=\frac{1}{1.2-1 }

COP= 5

We can also write Coefficient of performance (COP) of refrigeration cycle  as:

COP_R=\frac{Q_L}{W_i_n}

Amount of heat absorbed by low temperature reservoir can be found as:

Q_L=COP_R * W_i_n

Q_L=5 * 22 KJ

Q_L=110 KJ

According to first law of thermodynamics amount of heat rejected by hot reservoir is given by:

Q_H=Q_L + W_i_n

Q_H=110 KJ + 22 KJ

Q_H=132 KJ

We are given the mass of 0.96 kg. So,

q_H=\frac{Q_H}{m}

q_H=\frac{132 KJ}{0.96Kg}

q_H=137.5 KJ/Kg

Since it is a saturated liquid-vapour mixture q_H=h_f_g.

q_H=h_f_g=137.5 KJ/Kg

From Refrigerant 134-a tables T_H at h_f_g=137.5 KJ/Kg is 61.3 C. (We calculated this by interpolation)

Converting T_H from Celsius to Kelvin:

61.3^{o} C+273 = 334.3^{o} K

T_H= 334.3^{o} K

We are given:

T_H=1.2T_L

T_L=\frac{T_H}{1.2}

T_L=\frac{334.3}{1.2}

T_L=278.58^{o} K

Converting T_L from Kelvin to Celsius:

278.58^{o} K-273 = 5.58^{o} C

T_L= 5.58^{o} C

From Refrigerant 134-a tables P_m_i_n at T_L=5.58^{o} C is 356.9 KPa. (We calculated this by interpolation).

P_m_i_n= 356.9 KPa

8 0
4 years ago
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