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djyliett [7]
3 years ago
6

What is the inductive reactance of a 20 mH inductor at a frequency of 100Hz?

Engineering
1 answer:
Inessa05 [86]3 years ago
8 0

Answer:

The correct approach is "12.56 Ω".

Explanation:

The given values are:

Frequency,

f = 100 Hz

Inductor length,

L = 20 mH

Now,

The inductive reactance will be:

⇒ X_L=2 \pi fL

On putting the estimated values, we get

⇒       =2 (3.14)\times 100\times 20\times 10^{-3}

⇒       =12.56 \ \Omega

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Furkat [3]

To solve this problem it is necessary to apply the concepts related to the heat exchange of a body.

By definition heat exchange in terms of mass flow can be expressed as

W = \dot{m}c_p \Delta T

Where

C_p = Specific heat

\dot{m}= Mass flow rate

\Delta T = Change in Temperature

Our values are given as

C_p = 1.005kJ/kgK \rightarrow Specific heat of air

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From our equation we have that

W = \dot{m}c_p \Delta T

W = \dot{m}c_p (T_2-T_1)

Rearrange to find T_2

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3 years ago
A turboprop engine consists of a diffuser, compressor, combustor, turbine, and nozzle. The turbine drives a propeller as well as
Yuri [45]

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7 0
4 years ago
The Cv factor for a valve is 48. Compute the head loss when 30 GPM of water passes through the valve.
dlinn [17]

Answer:

The head loss in Psi is 0.390625 psi.

Explanation:

Fluid looses energy in the form of head loss. Fluid looses energy in the form of head loss when passes through the valve as well.

Given:

Factor cv is 48.

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GPM means gallon per minute.

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Step1

Expression for head loss for the water is given as follows:

c_{v}=\frac{Q}{\sqrt{h}}

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Step2

Substitute 48 for cv and 30 for Q in above equation as follows:

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{\sqrt{h}}=0.625

h = 0.390625 psi.

Thus, the head loss in Psi is 0.390625 psi.

 

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3 years ago
The metal control joints used to relieve stresses caused by expansion and contraction in large ceiling or wall expenses in inter
timurjin [86]

Answer:

It’s called Expansion Joints

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3 years ago
section 10.1 describes a man in the middle attack on the diffie-hellman key exhange protocal in which the adversary generates tw
nika2105 [10]

Answer:

1. James will attack by generating a random private key XD and a corresponding public key YD.

2. Jane transmit YA to another person called Alex.

3. James intercept YA and transmit YD to jane.

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At this point james and jane thinks they share a secret key but instead james has a secret key k1 to Jane and k2 to alex.

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6. James intercept and calculate k2 and vice versa.

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4 years ago
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