An organ.....................................................................................................
1)The limiting reactant will be aluminum acetate
2) The mass of aluminum hydroxide formed will be 9.75 grams.
<h3>Stoichiometric problem</h3>
The equation of the reaction is as below:
The mole ratio of the 2 reactants is 1:3.
Mole of 100 mL. 1.25 mol/L 
= 0.1 x 1.25 = 0.125 mol
Mole of 300 mL, 2.30 mol/L NaOH = 0.3 x 2.3 = 0.69 mol
Thus, aluminum acetate is limited.
Mole ratio of and 
= 1:1
Equivalent mole of = 0.125 mol
Mass of 0.125 mole = 0.125 x 78 = 9.75 grams.
More on stoichiometric calculations can be found here: brainly.com/question/27287858
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Answer: a person who studies research
<span>A wave that moves the matter it passes through up and down is a A) Transverse Wave, and one that moves the matter forward and back is a D) Longitudinal Wave.
There are two main types of waves, transverse and longitudinal, and I remember them by thinking that the longitudinal wave moves the matter in a longitudinal way (so forward and backward), and the transverse is the wave that moves the matter up and down — <em>a</em><em>cross </em>(since transverse can mean "across") the wave.
Hope this helped!! xx
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Atoms form a new substance by bonding with different atoms.
For example, hydrogen atoms and oxygen atoms bond to form H2O as per this equation:
2H2 + O2 ---> 2 H2O
To understand how to hydrogen and oxygen atoms form water you can write that as:
2 H - H + O - O ---> 2 H - O - H
Each hypen represent a chemical bond.
What is happening is that the H - H atoms and the O - O separate and bond with different atoms: H bonds to O which in turn bonds to other H.
Also, you have to know that chemical bonds are the result of interaction between the electrons of the valence shell of electrons of each atom. This is, valence electrons from O interact with valence electrons of H to form the bond H - O.
The interaction may be in different ways depending on the properties of the atoms: the kind of bonds known are metallic, ionic and covalent.
