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3 years ago

Portland cement (J. Aspdin) contains maximum % of CaO. Cement clinker contains

Chemistry

1 answer:

tatuchka [14]3 years ago

5 0

Answer:

The correct option is D

Explanation:

The major raw material used in making cement clinker is limestone. This limestone is usually mixed and heated with clay and can sometimes be mixed, in addition to the clay, with fly ash, black ash, bauxite, iron ore and gypsum. However, the product cement clinker contains different calcium silicates and/or aluminates such as Ca₃SiO₅, Ca₃Al₂O₆, Ca₂(Al,Fe)₂O₅ and Ca₂SiO₄. Thus, the correct option is D.

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In the third century B.C., King Hieron of Syracuse asked the famous mathematician Archimedes to determine if his crown was made

Llana [10]

Answer:

See explanation

Explanation:

a. I can conclusively tell if the crown was made of gold by measuring its density. First the mass of the crown is measured on a weighing balance. The crown is now put into a given volume of water and the volume of water displaced is accurately measured. The density of the crown is computed as mass/volume of fluid displaced. If the density of the crown is 19.3 g/mL, then it is made of solid gold.

b) When less valuable metals such as bronze or copper is mixed with gold in the crown, the density of the crown decreases and the crown becomes more brittle.

c) An object will float in a liquid when the density of the object is less than the density of the liquid. Hence the tendency of an object to float in a liquid depends on the density of the object and the density of the liquid.

d) Even though i do not know the results from your experiment but as regards the decision as to whether the object will float in the given liquid or not, reference must be made to the measured density of the object as well as the given density of the liquid. If the object is less dense (from values of density obtained from the experiment) than the liquid, then the object will float in the liquid and vice versa.

5 0

3 years ago

A gas is initially at a pressure of 225 kPa and a temperature of 245 K in a container that is 4.5 L. If the gas is compressed to

Artyom0805 [142]

Use the ideal gas equation PV=nRT. You can compare before and after using P1V1/n1T1=P2V2/n2T2. Since the number of moles remains constant you can disregard moles from the equation and use pressure, volume and temp. Make sure your pressure is converted to atmospheres, your volume is in liters, and your temperature is in kelvins.

6 0

3 years ago

A major component of gasoline is octane. When liquid octane is burned in air it reacts with oxygen gas to produce carbon dioxide

irakobra [83]

Answer:

0.267 mol

Explanation:

The unbalanced equation for the reaction that takes place is:

C₈H₁₈ + O₂ → H₂O + CO₂

Once we balance it we're left with:

2C₈H₁₈ + 25O₂ → 18H₂O + 16CO₂

Using the stoichiometric ratio of water and octane from the balanced reaction, we can convert mol of water into mol of octane:

2.40 mol H₂O * $\frac{2molC_8H_{18}}{18molH_2O}$ = 0.267 mol C₈H₁₈

Thus 0.267 moles of octane are needed to produce 2.40 mol of water.

5 0

3 years ago

Determine the net number of sigma bonds, the net number of pi bonds, and the overall bond order for N2+. Use 0.5 to indicate a f

trapecia [35]

Answer:

Net number of sigma bonds = 1

Net number of pi bonds = 2

Overall bond order = 3

Explanation:

Electronic configuration of N2 ia

1s2 2s2 2p3

There is head to head overlap in pz orbital. Thus, there is one sigma bond

Pi bond is formed whenever there is side wise overlapping. Since both px and py undergoes overlapping to form pi bond, there are two pi bonds

Bond order = 0.5 (bonding electron – antibonding electron)

= 0.5 (8-2) = 0.5*6 = 3

5 0

3 years ago

One way to represent this equilibrium is: 2 Al(s) 3 Br2(l)2 AlBr3(s) We could also write this reaction three other ways, listed

myrzilka [38]

The question is incomplete, the complete question is;

Aluminum metal and bromine liquid (red) react violently to make aluminum bromide (white powder). One way to represent this equilibrium is:

Al(s) + 3/2 Br2(l)AlBr3(s)

We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above.

1) 2 AlBr3(s) 2 Al(s) + 3 Br2(l)

2) 2 Al(s) + 3 Br2(l) 2 AlBr3(s)

3) AlBr3(s) Al(s) + 3/2 Br2(l)

Answer:

See explanation

Explanation:

We have that; Al(s) + 3/2 Br2(l)AlBr3(s)

So;

Al(s) + 3/2 Br₂(l) = AlBr₃(s)

K = [ AlBr₃] / [ Al] [ Br₂]³/²

K² = [ AlBr₃]² / [ Al ] ² [ Br₂]³

Now;

1) 2 AlBr₃ = 2 Al(s) + 3 Br₂(l) =

K₁ = [ Al ] ² [ Br₂]³ / [ AlBr₃]²

K₁ = ( 1 / K² ) = K⁻²

For the second reaction;

2 ) 2 Al(s) + 3 Br₂(l) = 2 AlBr₃(s)

K₂ = [ AlBr₃ ]² / [ Al ]² [ Br₂ ]³

K₂ = K²

For the third reaction;

3 )

AlBr₃(s) = Al(s) + 3/2 Br₂(l)

K₃ = [ Al ] [ Br₂ ] ³/² / [ AlBr₃ ]

= ( 1 / K ) = K⁻¹

7 0

3 years ago