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Scorpion4ik [409]
3 years ago
9

Mark tried to pour 36 ounces of tea into 3 cups. after filling the cup to the top, there were still 13.5 ounces left in his tea

pot. if each cup is the same size how much is in the tea cup? HELP PLEASE!
Mathematics
2 answers:
Dahasolnce [82]3 years ago
6 0

Answer:

its 12

Step-by-step explanation:

12 oz

Gekata [30.6K]3 years ago
5 0

Answer:

22.5/3

Step-by-step explanation:

Hey, the idea is to set up an equation that you can solve

36 ounces of tea = 3 cups(some ounces of tea) + 13.5 ounces left

Now just solve for how much tea is in each cup.

36-13.5 = 3(X)

3X = 22.5

x = 22.5/3

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C: (500 divided by 4)+(30 divided by 4)+2

Expanded form or expanded notation is a way of writing numbers to see the math value of individual digits. When numbers are separated into individual place values and decimal places they can also form a mathematical expression. 532 ÷ 4 in expanded notation form is (500 divided by 4)+(30 divided by 4)+2

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Which equation can pair with x-y=-2 to create a consistent and dependent system?
MrRissso [65]

See the explanation

<h2>Explanation:</h2>

A system that has one or infinitely many solutions is called <em>consistent. </em>If an equation in a system tells us no new information then the equations of the system are <em>dependent. </em>In other words, to find an equation that creates a consistent and dependent system with the given equation we have to get the same line:

The given line is:

x-y=-2

If we multiply both sides of the equation by a constant we will have the same line when plotting, therefore let's multiply by 3:

3(x-y)=3(-2) \\ \\ 3x-3y=-6

So a system of two linear equation that is consistent and dependent is:

\left \{ {{x-y=-2} \atop {3x-3y=-6}} \right.

<h2>Learn more:</h2>

Graph of lines: brainly.com/question/14434483#

#LearnWithBrainly

3 0
4 years ago
How to simplify 4/10 what's the answer?
Pani-rosa [81]
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3 years ago
In tossing four fair dice, what is the probability of tossing, at most, one 3
11Alexandr11 [23.1K]

<u>Answer- </u>

In tossing four fair dice, the probability of getting at most one 3 is 0.86.

<u>Solution-</u>

The probability of getting at most one 3 is, either getting zero 3 or only one 3.

P(A) =The \ probability \ of \ getting \ zero \ 3 =(\frac{5}{6})(\frac{5}{6})(\frac{5}{6})(\frac{5}{6})=\frac{625}{1296} =0.48                    ( ∵ xxxx )

P(B) = The \ probability \ of \ getting \ only \ one \ 3 =(4)(\frac{1}{6})(\frac{5}{6})(\frac{5}{6})(\frac{5}{6}) = 0.38                    ( ∵ 3xxx, x3xx, xx3x, xxx3 )

P(Atmost one 3) = P(A) + P(B) = 0.48 + 0.38 = 0.86

7 0
3 years ago
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