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Rom4ik [11]
3 years ago
5

What is the mole ratio of aluminum to chlorine in the compound aluminum

Chemistry
1 answer:
creativ13 [48]3 years ago
6 0
1:3
The ratio of Al3+ ions to Cl− ions in the chemical formula is 1:3.
I’m sorry if this didn’t help I’m new to Brainly
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If black fur is dominant in rabbits, is it ever possible for two black fur rabbits to produce a white fur offspring?
tatyana61 [14]

Answer:

No

Explanation:

It is not possible because the Black fur is the dominant gene and White fur is not therefor if both rabbits have black fur it is impossible for the offspring of the rabbits to have white fur.

3 0
2 years ago
_Al2O3+heat=_Al+_O2​
Natalka [10]

Answer:

6.

2AI2O3 + heat ->  4AI + 3O2

Reaction type: Combustion

7.

2AI+ 6HCl -> 3H2 + 2AlCl3

Reaction type: Single Replacement

8.

IDK

Reaction type: Double Replacement?

Explanation:

8 0
2 years ago
51. The radius of gold is 144 pm and the density is 19.32 g/cm3. Does elemental gold have a face-centered cubic structure or a b
Serjik [45]

Answer:

Elemental gold to have a Face-centered cubic structure.

Explanation:

From the information given:

Radius of gold = 144 pm

Its density = 19.32 g/cm³

Assuming the structure is a face-centered cubic structure, we can determine the density of the crystal by using the following:

a = \sqrt{8} r

a = \sqrt{8} \times 144 pm

a = 407 pm

In a unit cell, Volume (V) = a³

V = (407 pm)³

V = 6.74 × 10⁷ pm³

V = 6.74 × 10⁻²³ cm³

Recall that:

Net no. of an atom in an FCC unit cell = 4

Thus;

density = \dfrac{mass}{volume}

density = \dfrac{ 4 \ atm ( 196.97 \ g/mol) (\dfrac{1 \ mol }{6.022 \times 10^{23} \ atoms})}{6.74 \times 10^{-23} \ cm^3}

density d = 19.41 g/cm³

Similarly; For a  body-centered cubic structure

r = \dfrac{\sqrt{3}}{4}a

where;

r = 144

144 = \dfrac{\sqrt{3}}{4}a

a = \dfrac{144 \times 4}{\sqrt{3}}

a = 332.56 pm

In a unit cell, Volume V = a³

V = (332.56 pm)³

V = 3.68 × 10⁷ pm³

V  3.68 × 10⁻²³   cm³

Recall that:

Net no. of atoms in BCC cell = 2

∴

density = \dfrac{mass}{volume}

density = \dfrac{ 2 \ atm ( 196.97 \ g/mol) (\dfrac{1 \ mol }{6.022 \times 10^{23} \ atoms})}{3.68 \times 10^{-23} \ cm^3}

density =17.78 g/cm³

From the two calculate densities, we will realize that the density in the face-centered cubic structure is closer to the given density.

This makes the elemental gold to have a Face-centered cubic structure.

3 0
3 years ago
in this trial, 0.400 M NaOH was added to 40.00 ml of 0.400 M HCl. How many ml of base must be added to cause the colour to chang
denis-greek [22]

Answer:

The amount of Ml that is needed

6 0
2 years ago
The nutritional energy content (in Calories) present in 86g of broccoli with 6g of carbohydrates, 2.6g of protein, and 0.3g of f
asambeis [7]

Answer:

37.1 calories.

Approximately, 37.1 = 40 calories.

Explanation:

So, without mincing words let's dive straight into the solution to the question above.

We are given the following parameters which are going to help in solving this particular Question.

The mass of broccoli = 86g of broccoli, mass of carbohydrates present = 6g of carbohydrates, the mass of protein present = 2.6g of protein and the mass of fat present = 0.3g of fat.

Therefore, the nutritional energy content (in Calories) = (6 × 4) + (2.6 × 4) + (0.3 × 9) = 10.4 + 24 + 2.7 = 37.1

Hence, the nutritional energy content (in Calories) = 37.1 calories.

Approximately, 37.1 = 40 calories.

5 0
2 years ago
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