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Dahasolnce [82]
3 years ago
5

What is the pOH value of 0.0000877 M HCL

Chemistry
1 answer:
ki77a [65]3 years ago
7 0

Answer:

pOH=9.9

Explanation:

pH=-log[H+]= -log[0.0000877]

=4.06

pOH+ pH=14

pOH=14-4.06= 9.91

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3 years ago
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In a hospital laboratory, a 10.0 mL sample of gastric juice (predominantly HCl), obtained several hours after a meal, was titrat
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n_1M_1V_1=n_2M_2V_2

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are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=?\\V_1=10.0mL\\n_2=1\\M_2=0.1M\\V_2=7.2mL

Putting values in above equation, we get:

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To calculate pH of gastric juice:

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3 years ago
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Answer:

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