Answer:
is the solubility of
in 0.10 M
.
Explanation:
Concentration of calcium nitrate = ![[Ca(NO_3)_2]=0.10 M](https://tex.z-dn.net/?f=%5BCa%28NO_3%29_2%5D%3D0.10%20M)

![[Ca(NO_3)_2]=0.10 M=[Ca^{2+}]](https://tex.z-dn.net/?f=%5BCa%28NO_3%29_2%5D%3D0.10%20M%3D%5BCa%5E%7B2%2B%7D%5D)
Solubility product of the calcium fluoride = 
Solubility of calcium fluoride in calcium nitrate solution :

(0.10+S) (2S)
The expression of solubility is given by :
![K_{sp}=[Ca^{2+}][F^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BCa%5E%7B2%2B%7D%5D%5BF%5E-%5D%5E2)

Solving for S:

is the solubility of
in 0.10 M
.
Rubidium (Rb) is in group 1, so it has a valence charge of +1.
Chlorine (Cl) is in group 17 or the halogens, so it has a valence charge of -1.
Since both elements have the same valence charges, just of opposite signs, this means that only 1 atom of each element is needed to create a stable bond. The formula for rubidium chloride will be RbCl.
The answer to your question is two protons and two neutrons.
Answer:
False
Explanation:
Single-celled organisms use cell division as their method of reproduction. Humans are not single celled, we are multicellular, therefore this conclusion is incorrect.
Hope this helps :)