Explanation:
Given that,
The optical power of the equivalent single lens is 45.4 diopters.
(a) The relationship between the focal length and the focal length is given by:
![f=\dfrac{1}{P}](https://tex.z-dn.net/?f=f%3D%5Cdfrac%7B1%7D%7BP%7D)
![f=\dfrac{1}{45.4}](https://tex.z-dn.net/?f=f%3D%5Cdfrac%7B1%7D%7B45.4%7D)
f = 0.022 m
or
f = 2.2 cm
(b) We need to find how far in front of the retina is this "equivalent lens" located. It is given by using lens formula as :
![\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bv%7D-%5Cdfrac%7B1%7D%7Bu%7D%3D%5Cdfrac%7B1%7D%7Bf%7D)
Here, u = infinity
![\dfrac{1}{v}=\dfrac{1}{2.2}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bv%7D%3D%5Cdfrac%7B1%7D%7B2.2%7D)
v = 2.2 cm
So, at 2.2 cm in front of the retina is this "equivalent lens" located.
Hence, this is the required solution.
The answer is:
It is a measure of the strength of the bonds between ions.
Lattice energy is an estimate of the strength of the bonds formed by ionic compounds.
The first two choices are wrong because it is actually the opposite.
- As the ion size increases, lattice energy <u>decreases</u>.
- As charge of ions increases, lattice energy <u>increases</u>
As for the other third option, it is wrong because lattice energy is the energy RELEASED not absorbed.
Answer: Here's your answer: The great uses of Electromagnetism in Life. Whatever powered devices we use, from table clocks to microwave ovens, have some form of electromagnetic principle involved in their functioning. It is electromagnetism which has given the flexibility for switching of/on electricity as required.
Explanation: Yw and mark me as brainiest
Answer: ![3.66(10)^{33}kg](https://tex.z-dn.net/?f=3.66%2810%29%5E%7B33%7Dkg)
Explanation:
We are told both planets describe a circular orbit around the star S. So, let's approach this problem begining with the angular velocity
of the planet P1 with a period
:
(1)
Where:
is the velocity of planet P1
is the radius of the orbit of planet P1
Finding
:
(2)
(3)
(4)
On the other hand, we know the gravitational force
between the star S with mass
and the planet P1 with mass
is:
(5)
Where
is the Gravitational Constant and its value is ![6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}](https://tex.z-dn.net/?f=6.674%2810%29%5E%7B-11%7D%5Cfrac%7Bm%5E%7B3%7D%7D%7Bkgs%5E%7B2%7D%7D)
In addition, the centripetal force
exerted on the planet is:
(6)
Assuming this system is in equilibrium:
(7)
Substituting (5) and (6) in (7):
(8)
Finding
:
(9)
(10)
Finally:
(11) This is the mass of the star S