Answer:
Answered
Explanation:
v= 1 m/s
A= 1 m^2
m= 100 kg
y= 1 mm
μ = ?
ζ= viscosity of SAE 20 crankcase oil of 15° C= 0.3075 N sec/m^2
forces acting on the block are
F_s ← ↓ →F_f
mg
N= mg
F_s= shear force = ζAv/y F_f= friction force = μN
now in x- direction F_s= F_f
ζAv/y = μN
0.3075×1×1×1/1×10^{-3} = μ×100
⇒μ=0.313 (coefficient of sliding friction for the block)
Now, as the velocity is increased shear force also increases and due to this frictional force also increases.
Now, to compensate this frictional force friction coefficient must increase
as v∝μ
The answer is number 2 stomata.
As a result of the bank, the vertical component of the lift has lessened.
Charged objects have a Net charge.
Wavelength=velocity/frequency
Time a.k.a period = 1/frequency
Step 1: solve for frequency using the first equation
0.79m = 355/frequency
Frequency=280.45 Hz
Step 2: solve the period using the second equation
1/280.45 = 0.00357=3.57*10^-3 seconds