Answer:
Explanation:
entire mixture = 5.32g
F = 3.12g --> 3.12g*(1mol/18.998g) = 0.1642mols F
Since LiF has 1mol Li to 1 mol F,
0.1642mols F* (1mol Li/1 mol F) = 0.1642mols Li
Convert into grams:
0.1642mols Li * (6.94g/1mol) =1.1397g Li
So add the masses of Li and F together:
3.12g F + 1.1397g Li = 4.2597g LiF
5.32g - 4.2597g LiF = 1.06g KF
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Basically what we did is convert the given mass of F to mols and since we know that there is a 1:1 mole ratio of F to L, the number of mols of F is the number of mols of Li. Change the mols of Li to grams and then add the mass of Li with given mass of F. You now have the mass of LiF. To find mass of KF, subtract mass of LiF from mass of entire mixture.
By dividing the percentage composition with the molar mass of that element we will get the empirical formula. Then using that empirical formula and formula mass we can find the molecular formula.
<u>Explanation:</u>
The chemical properties of any substance are defined obviously by the different types and relative amounts of atoms constituting its primary entities (in case of covalent compounds the primary entities are molecules and ions in the event of ionic compounds).
A percent composition of any compound gives the mass percent of each element present in the compound; in addition to that frequently it is determined experimentally and utilized to derive an empirical formula of any compound. An empirical formula mass of any covalent compound could be comparable with the molar or molecular mass of a compound to acquire a molecular formula.
It happens with starch granules!