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son4ous [18]
3 years ago
8

A horse pulls a cart along a flat road. Consider the following four forces that arise in this situation. (1) the force of the ho

rse pulling on the cart (2) the force of the cart pulling on the horse (3) the force of the horse pushing on the road (4) the force of the road pushing on the horse Suppose that the horse and cart have started from rest; and as time goes on, their speed increases in the same direction. Which one of the following conclusions is correct concerning the magnitudes of the forces mentioned above?
Physics
1 answer:
expeople1 [14]3 years ago
3 0

Complete Question: A horse pulls a cart along a flat road. Consider the following four forces that arise in this situation. (1) the force of the horse pulling on the cart (2) the force of the cart pulling on the horse (3) the force of the horse pushing on the road (4) the force of the road pushing on the horse Suppose that the horse and cart have started from rest; and as time goes on, their speed increases in the same direction. Which one of the following conclusions is correct concerning the magnitudes of the forces mentioned above?

A) Force 1 exceeds force 2.

B) Force 2 is less than force 3.

C) Force 2 exceeds force 4.

D) Force 3 exceeds force 4.

E) Forces 1 and 2 cannot have equal magnitudes.

Answer: B) Force 2 is less than force 3.

Explanation: From the given four forces to be considered, Force 2 is less than Force 3 is correct option.

After evaluating the forces one by one. Force 3 and Force 4 are the same, both have equal magnitude.

And Force 3 is greater than Force 2, i.e., the force of the horse pushing on the road is much higher than the cart pulling the horse. Hence, more forces is required to pull the cart while on the road towards forward direction.

More so, the force of the road pushing on the horse is greater than the force of the cart pulling on the horse.

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A muon has a rest mass energy of 105.7 MeV, and it decays into an electron and a massless particle. If all the lost mass is conv
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Answer:

The electron’s velocity is 0.9999 c m/s.

Explanation:

Given that,

Rest mass energy of muon = 105.7 MeV

We know the rest mass of electron = 0.511 Mev

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Using formula of energy

K_{rel}=(\gamma-1)mc^2

\dfrac{K_{rel}}{mc^2}=\gamma-1

Put the value into the formula

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We need to calculate the electron’s velocity

Using formula of velocity

\gamma=\dfrac{1}{\sqrt{1-(\dfrac{v}{c})^2}}

\gamma^2=\dfrac{1}{1-\dfrac{v^2}{c^2}}

\gamma^2-\gamma^2\times\dfrac{v^2}{c^2}=1

v^2=\dfrac{1-\gamma^2}{-\gamma^2}\times c^2

Put the value into the formula

v^2=\dfrac{1-(208)^2}{-208^2}\times c^2

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