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Svetlanka [38]
3 years ago
14

Electronegativity6. Which one of the following bonds is the least polar one?

Chemistry
1 answer:
Sliva [168]3 years ago
8 0
I think C-I

It can also be wrong but that’s my opinion
You might be interested in
Strontium, a group 2 element with an electron configuration of 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 , will form a _____
amid [387]

Answer:

Strontium, a group 2 element with an electron configuration of 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² , will form a +2 ion in a chemical bond.

Explanation:

An ionic bond is produced between metallic and non-metallic atoms, where electrons are completely transferred from one atom to another. During this process, one atom loses electrons and another one gains them, forming ions. Usually, the metal gives up its electrons forming a cation to the nonmetal element, which forms an anion.

So an ion is an atom or group of atoms that have an electric charge. A cation is an ion that has a positive charge.

The alkali metals in the earth (Elements IIA) lose two electrons to form a 2+ cation. Strontium is an alkali metal that loses the two electrons belonging to 5s², forming the +2 ion.

5 0
2 years ago
What is the volume of 3.89 grams of helium gas?
lukranit [14]

Answer: There are 971.77 millimoles in 3.89 grams of Helium

Explanation:

i think its right im not really sure

7 0
3 years ago
What is the ph of a solution of 0.700 m kh2po4, potassium dihydrogen phosphate?
GalinKa [24]
Molal or molar? There is a difference
4 0
3 years ago
The specific heat of zinc is 0.39 J/g*°C. How much energy needed to change the temperature of 34g of zinc from 22°C to 57°C. Is
Svetlanka [38]

Answer:

464.1 J absorbed.

Explanation:

Given data:

Specific heat of zinc =  0.39 J/g°C

Mass of zinc = 34 g

Temperature changes = 22°C to 57°C

Energy absorbed or released = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 57°C -  22°C

ΔT = 35°C

Q = m.c. ΔT

Q = 34 g. 0.39 J/g°C. 35°C

Q = 464.1 J

6 0
3 years ago
What element has the smallest atomic radius
Mariulka [41]
Helium has the smallest atomic radius® Α⇒Ω
4 0
3 years ago
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