<span>Density is a mathematical expression that calculates the mass of the object by its volume:
Data:
m (mass) = 5 grams
v (volume) </span>≈ 0.689 cm³
d (density) = ?
Formula:
Solving:
Answer:
a. C(t)=205*(1-0.08)^t
b. t=log_0.92(C(t)/205)=(log_10(C(t)/205))/(log_10(0.92))
c. 16.92 hours
Step-by-step explanation:
Let's say that C(t) is the expression of the amount of caffeine remaining in Darrin's system after t time, hours in this particular case.
a. Then for the first hour the expression would be:
C(t)=205*(1-0.08)
For the second hour:
C(t)=205*(1-0.08)-205*(1-0.08)*(1-0.08)
For the third
C(t)=205*(1-0.08)-205*(1-0.08)*(1-0.08)-205*(1-0.08)*(1-0.08)*(1-0.08)
And so on, for that reason the best way to fit the expression is:
C(t)=205*(1-0.08)^t
2. To find the correct expression for time, we must solve for t the equation recently written above:
Considering that log_b(a)=c and log_b(a)=log_c(a)/log_c(b), then:
t=log_0.92(C(t)/205)
t= (log_10(C(t)/205))/(log_10(0.92))
3. Finally we replace the given value of C(t) into the equation for t:
t= (log_10(50/205))/(log_10(0.92))=16.92
t= 16.92 hours
Answer:
AC=13.6
Step-by-step explanation:
let the triangle is ABC
radius =6 , diameter =6*2=12
therefore AB=12
since BC is a tangent
therefore angle B =90 degrees
BC=6.4
AC=13.6
Answer:
16.75 meters
Step-by-step explanation:
This problem is a plug in problem.
H = 0.20x + 12.75
we plug in 20 for x which gives us
(0.20 * 20) + 12.75
which equals
4 + 12.75
giving us
16.75 meters
Answer:
3
Step-by-step explanation:
First right out all the data in numerical order from left to right.
2, 2, 2, 3, 4, 5, 7
The median is the middle number in the set. If there is an even amount of data points, find the average of the two middle numbers. If there is an odd number of data points, like in this data set, just take the middle number as you median.
There are 7 data points in this set so the fourth number in the set written in numerical order would be your median.
When writing this set out in numerical order, repeated numbers must be repeated, we find that the fourth, or middle, number is 3. Therefore, 3 is the median of this data set.