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3 years ago

What is the approximate latitude and longitude or location A

Physics

1 answer:

yulyashka [42]3 years ago

5 0

Answer:

latitude = 44.326859 and longitude = -71.213783

Explanation:

latitude = 44.326859 and longitude = -71.213783

You might be interested in

How many swings would a 23 cm long pendulum make in 30 seconds?

iragen [17]

Is there any possible chance that at some point in your science
studies, sometime before you were given this question for your
homework, that maybe you might have encountered this formula
for the period of a simple pendulum ?

   Period = (2 pi) √(length/gravity) .

If the length is 0.23 meter, and the
acceleration of gravity is 9.8 m/s²,
then the period is

   = (2 pi) √(0.23/9.8)

   = 0.963... second (rounded)

That's how long it takes for a simple pendulum, 23cm long,
hanging on a massless string and not swinging too far to
the side, to complete one full swing left and right.

Now, if you can figure out how many periods of 0.963 second
there are in 30 seconds, you'll have your answer. I'll leave
that part of it to you.

8 0

3 years ago

A phonograph turntable rotating at 33 1 3 rev/min slows down and stops in 1.98 min. (Assume the turntable initially rotates in t

enyata [817]

Explanation:

photography presente in frame was of 11 meter thats why

6 0

3 years ago

Polarizers 1 and 3 have their axes of polarization indicated by the black solid lines, perpendicular to each other. Polarizer 2

Marysya12 [62]

Answer:

percentage of unpolarized light intensity,

$\frac{I"'}{I} = 8.52%$

Given:

Polarization angle for the 2nd polarizer, $\theta = 50.9^{\circ}$

Solution:

If I be the intensity of unpolarized light, then the intensity of light passing through the first polarizer, I':

$I' = \frac{I}{2}$

Now, the intensity of light through polarizer 2, I":

$I" = I'cos^{2}\theta = \frac{I}{2}cos^{2}\theta$

Also Polarizer 1 and 3 are perpendicular to each other:

Therefore, $\theta' = 90^{\circ} - 50.9^{\circ} = 49.1^{\circ}$

Intensity of light passing through polarizer 3:

$I"' = I" cos^{2}\theta' = \frac{I}{2}cos^{2}\theta cos^{2}\theta'$

$I"' = \frac{I}{2}cos^{2}50.9^{\circ}\times cos^{2}49.1^{\circ}$

I"' = 0.0852 I

Now, percentage of unpolarized light intensity:

$\frac{I"'}{I}\times 100 = 0.0852\times 100 = 8.52%$

3 0

3 years ago

A certain electric circuit obeys Ohm's law. If the voltage across the circuit and the resistance of the circuit are both doubled

rusak2 [61]

Answer:

Current remains constant

Explanation:

From Ohm's law we know that V=IR where V is voltage across the circuit, I is the current across circuit and R is resistance. Making I the subject of the formula then

$I=\frac {V}{R}$