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joja [24]
3 years ago
13

PLEASE PLEASE HELP ME ILL GIVE U BRAINLIEST JUST FILL IN THE BLANKS

Physics
1 answer:
White raven [17]3 years ago
6 0

Answer:

<em>38 kg.m/s</em>

Explanation:

<u>Momentum </u>

Momentum is often defined as "mass in motion".

Since all objects have mass, if it's moving, then it has momentum. The momentum is a vector and It can be calculated as the product of the mass by the velocity of the object:

\vec p = m\vec v

If only magnitudes are considered:

p = mv

We are given that an m=9.5 kg turkey is running at v=4 m/s. Below is the formatted data:

p = ?

m = 9.5 kg

v = 4 m/s

Formula

p = m v

p = 9.5 \cdot 4

p = 38 kg.m/s

The filled table is included below

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How does heat energy move by convection when a cook heats a pot of water?
laiz [17]

The correct choice is

B. Particles at the bottom of the water carry heat energy to the top of the water.

when pot of water is heater, the bottom of pot gets heated. the particles of water in contact with the bottom of the pot gets heat through conduction. after getting heat, these particles of water near the bottom, move away towards top and their position is taken by cooler particles from top. that way heat travels

3 0
3 years ago
Read 2 more answers
Our eyes are typically 6 cm apart. Suppose you are somewhat unique, and yours are 9.50 cm apart. You see an object jump from sid
Serhud [2]

Answer: 12.67 cm, 8 cm

Explanation:

Given

Normal distance of separation of eyes, d(n) = 6 cm

Distance of separation is your eyes, d(y) = 9.5 cm

Angle created during the jump, θ = 0.75°

To solve this, we use the formula,

θ = d/r, where

θ = angle created during the jump

d = separation between the eyes

r = distance from the object

θ = d/r

0.75 = 9.5 / r

r = 9.5 / 0.75

r = 12.67 cm

θ = d/r

0.75 = 6 / r

r = 6 / 0.75

r = 8 cm

Thus, the object is 12.67 cm far away in your own "unique" eyes, and just 8 cm further away to the normal person eye

8 0
4 years ago
A small logo is embedded in a thick block of crown glass (n = 1.52), 4.70 cm beneath the top surface of the glass. The block is
harkovskaia [24]

The concept required to solve this problem is the optical relationship that exists between the apparent depth and actual or actual depth. This is mathematically expressed under the equations.

d'w = d_w (\frac{n_{air}}{n_w})+d_g (\frac{n_{air}}{n_g})

Where,

d_g = Depth of glass

n_w = Refraction index of water

n_g = Refraction index of glass

n_{air} = Refraction index of air

d_w = Depth of water

I enclose a diagram for a better understanding of the problem, in this way we can determine that the apparent depth in the water of the logo would be subject to

d'w = d_w (\frac{n_{air}}{n_w})+d_g (\frac{n_{air}}{n_g})

d'w = (1.7cm) (\frac{1}{1.33})+(4.2cm)(\frac{1}{1.52})

d'w = 4.041cm

Therefore the distance below the upper surface of the water that appears to be the logo is 4.041cm

3 0
3 years ago
If two is company and three is a crowd, what is 4 and 5?
LiRa [457]

4 and 5 is 9

(4 + 5)

4 0
4 years ago
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Which of the following best explains why most chemical reactions proceed more quickly when the concentrations of reactants are i
nekit [7.7K]
A More concentrated means more collisions per unit volume, and as the volume stays the same and only concentration changes, the there are more collisions
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