Answer:
<h3>The answer is option D</h3>
Explanation:
To find the speed given the kinetic energy and mass we use the formula

where
m is the mass
v is the speed
From the question
KE = 15 J
m = 2.3 kg
We have

We have the final answer as
<h3>3.6 m/s</h3>
Hope this helps you
Answer:
63.5 w isvthebanswerok is th answer
Answer: 34.4 g
Explanation:


As
is in excess,
is the limiting reagent and thus it will limit the formation of products.

According to stoichiometry:
2 moles of hydrogen produce = 1 mole of 
2.5 moles of hydrogen produce =
of 
Mass of 
But as % yield is 86%, mass of
produded is 
Thus 34.4 g of
is produced.
Anywhere between 5sogt2 and 776sogt2