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marysya [2.9K]
2 years ago
7

Awdawdawdadawdanodawdadwadadaw

Chemistry
1 answer:
crimeas [40]2 years ago
3 0
No, actually adawadawada and awawawaw usually addawadadaw but also awawawa so it’s a possibility but very rare.
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A student makes a sandwich with several layers of bread and cheese. Then the student cuts the sandwich and says it models how a
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Rock layer and sandwich layer is almost the same.

Why are rock layers are like sandwiches?

This geologic structure is called an anticline. Now gently bend your sandwich so that the layers are bowed downwards, thus creating a syncline. The presence of anticlines and synclines indicate strong forces that often form mountain ranges.

7 0
3 years ago
A nuclear waste site. cesium-137 is a particularly dangerous by-product of nuclear reactors. it has a half-life of 30 years. it
hram777 [196]
The mass decay rate is of the form
m(t) = m_{0} e^{-kt}
where
m₀ = 3000 g,the initial mass
k = the decay constant
t = time, years.

Because the half-life is 30 years, therefore
e^{-30k} =  \frac{1}{2} \\\ -30k = ln(0.5) \\ k =  \frac{ln(0.5)}{-30} =0.0231

After 60 years, the mass remaining is
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4 0
3 years ago
Why does grinding solid crystals increase the rate of dissolving for a solid solute in water? smaller crystals are more polar. s
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The answer is...

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4 0
3 years ago
Three-quarters of the elements are..
Dennis_Churaev [7]

Answer:

metals

Explanation:

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8 0
3 years ago
In the Bohr model of the hydrogen atom, an electron moves in a circular path around a proton. The speed of the electron is appro
Zolol [24]

This is an incomplete question, here is a complete question.

In the Bohr model of the hydrogen atom, an electron moves in a circular path around a proton. The speed of the electron is approximately 2.15\times 10^6m/s?

Find the force acting on the electron as it revolves in a circular orbit of radius 5.34\times 10^{-11}m.

Answer : The force acting on electron is, 7.9\times 10^{-8}N

Explanation :

Formula used :

F=\frac{mv^2}{r}

where,

F = force acting on electrons

m = mass of electrons = 9.1\times 10^{-31}kg

v = speed of electron = 2.15\times 10^6m/s

r = radius of circular orbit = 5.34\times 10^{-11}m

Now put all the given values in the above formula, we get:

F=\frac{(9.1\times 10^{-31}kg)\times (2.15\times 10^6m/s)^2}{5.34\times 10^{-11}m}

F=7.9\times 10^{-8}N

Thus, the force acting on electron is, 7.9\times 10^{-8}N

8 0
3 years ago
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