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3 years ago

Awdawdawdadawdanodawdadwadadaw

Chemistry

1 answer:

crimeas [40]3 years ago

3 0

No, actually adawadawada and awawawaw usually addawadadaw but also awawawa so it’s a possibility but very rare.

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Hurricanes derive their energy from: Group of answer choices the latent heat of condensation. the latent heat of fusion. the lat

klemol [59]

Hurricanes derive their energy from the Latent heat of condensation.

Hence, Option (1) is correct answer.

<h3>What is Latent Heat ? </h3>

The heat that is released or absorbed during a phase change of a substance is known as Latent heat.

<h3>What is Hurricanes ?</h3>

Hurricanes is basically a type of storm called a tropical cyclone. These are intense low pressure areas. Hurricanes derive their energy from the latent heat of CONDENSATION.

Thus from the above conclusion we can say that Hurricanes derive their energy from the Latent heat of condensation.

Hence, Option (1) is correct answer.

Learn more about the Latent heat here: brainly.com/question/5401454

#SPJ4

7 0

2 years ago

If 0.500 mol of NaN3 react what mass I'm grams of nitrogen would result

klemol [59]

Looks like 3*.5 mol of N, or 1.5*.5 N2
<span>convert that to grams.</span>

6 0

3 years ago

Chlorine is used to disinfect swimming pools. the accepted concentration for this purpose is 1.00 ppm chlorine, or 1.00 g of chl

frez [133]

The accepted concentration of chlorine is 1.00 ppm that is 1 gram of chlorine per million of water.

The volume of water is $2.29\times 10^{4} gal$ .

Since, 1 gal= 3785.41 mL

Thus, $2.29\times 10^{4} gal=2.29\times 10^{4}\times 3785.41 mL=8.66\times 10^{7}mL$

Density of water is 1 g/mL thus, mass of water will be $8.66\times 10^{7}g$ .

Since, 1 grams of chlorine → $10^{6}$ grams of water.

1 g of water → $10^{-6}$ g of chlorine and,

$8.66\times 10^{7}g$ of water →86.6 g of chlorine

Since, the solution is 9% chlorine by mass, the volume of solution will be:

$V=\frac{100}{9}\times 86.6 mL=9.62\times 10^{2} mL$

Thus, volume of chlorine solution is 9.62\times 10^{2} mL.

6 0

3 years ago

The edge length of the unit cell of KCl (NaCl-like structure, FCC) is 6.28 Å. Assuming anion-cation contact along the cell edge,

Mila [183]

Answer:

1.33 Å

Explanation:

Given that the edge length , a of the KCl which forms the FCC lattice = 6.28 Å

Also,

For the FCC lattice in which the anion-cation contact along the cell edge , the ratio of the radius of the cation to that of anion is 0.731.

Thus,

$\frac {r^+}{r^-}=0.731$ .................1

Also, the sum of the radius of the cation and the anion in FCC is equal to half of the edge length.

Thus,

$r^++r^-=\frac {a}{2}$ ...................2

Given that:

$Cl^-\ (r^-) = 1.82\ \dot{A}$

To find,

$K^+\ (r^+) = ? \dot{A}$

Using 1 and 2 , we get:

$1.731\ r^+=0.731\times \frac {6.28}{2}$

<u>Size of the potassium ion = 1.33 Å</u>

4 0

3 years ago

I’m to lazy can anyone help me please

katen-ka-za [31]

Answer: what do i have to do to help.. ;-; like i need instructions and why are the words coverd off black??

;-;

Explanation:

6 0

3 years ago