We know, F = k * q₁ * q₂ / r²

Substitute the known values,
F = 9 * 10⁹ * 5 * 7 / (1.2)²

F = 315 * 10⁹ / 1.44

F = 218.75 * 10⁹ N

F = 2.1875 * 10¹¹ N [ Final Answer ]

Hope this helps!

5 0

4 years ago

Runner A takes 45 s to run 400 m. Runner B takes 48 s to run the same distance. Which runner has the greater average speed?

Natalka [10]

Runner A because they completed it in a less amount of time

6 0

2 years ago

A gray kangaroo can bound across a flat stretch of ground with each jump carrying it 10 m from the takeoff point. you may want t

Stells [14]

<u>Answer:</u>

Takeoff speed of Kangaroo = 12.91 m/s

<u>Explanation:</u>

The distance reached by Kangaroo = 10 meter

Angle at which it jumps = 18°

The motion of Kangaroo is like a projectile, the distance traveled is the range of projectile.

Range of projectile = Time taken for the projectile to reach ground* Horizontal velocity

Time taken for the projectile to reach ground:

Time taken = Two times of the time taken for the projectile to reach maximum height

Time taken for the projectile to reach maximum height = Vertical speed / Acceleration = u sin θ/g

Time taken for the projectile to reach ground = 2 u sin θ/g

So Range of projectile = $ucos\theta*\frac{2usin\theta}{g} =\frac{u^2sin2\theta}{g}$

We have Range = 10 meter, θ = 18⁰

Substituting

$10=\frac{u^2sin(2*18)}{9.8}\\ \\ u^2= 166.73\\ \\ u=12.91 m/s$

Takeoff speed of Kangaroo = 12.91 m/s

3 0

3 years ago

Read 2 more answers

A ball is dropped off the top of a 35 meter tall building. How fast will it be going when it reaches

4vir4ik [10]

1 Times 35 that’s your answer

5 0

4 years ago