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il63 [147K]
2 years ago
7

The vertices of a triangle are listed below:

Mathematics
1 answer:
Pavlova-9 [17]2 years ago
6 0
I believe it’s 20, hope this helps!
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What is the value of x?<br><br>enter your answer in the box<br><br>X__​
vfiekz [6]
<h3>Answer: x = 5</h3>

=====================

Work Shown:

Angle Bisector Theorem

9/(2x-1) = 15/3x

9*3x = 15(2x-1) ... cross multiply

27x = 30x-15

27-30x = 30x-15-30x ... subtract 30x from both sides

-3x = -15

-3x/(-3) = -15/(-3) .... divide both sides by -3

x = 5

6 0
3 years ago
-5(x+1)+3x=6-(4x-3) solve for x
PilotLPTM [1.2K]

Answer: x = -3

Step-by-step explanation:Step by step solution :

Step  1  :

Pulling out like terms :

1.1     Pull out like factors :

  -x - 3  =   -1 • (x + 3)  

Equation at the end of step  1  :

Step  2  :

Solving a Single Variable Equation :

2.1      Solve  :    -x-3 = 0  

Add  3  to both sides of the equation :  

                     -x = 3  

Multiply both sides of the equation by (-1) :  x = -3  

One solution was found :

                  x = -3

7 0
3 years ago
3. The three salespeople for a local advertising firm are Lola, Ahmed, and Tommy. Lola sold $2030 in ads, Ahmed sold $1540, and
dalvyx [7]
A.) First, you find the total sales. $2030 + $1540 + $1800 = $5370. Then, divide each with the total. The answer would be:

Lola: 203/537
Ahmed: 154/537
Tommy: 60/179

b.) Divide 100 by 3 for equal shares. Each person receives $33.3.
6 0
3 years ago
Use calculus to find the first order conditions. Use solver then to solve the first order conditions. Show your work for the fir
DaniilM [7]

The values of x and y are 70/22 and 30/22 respectively by using the first-order condition of differential calculus.

<h3>What is the first-order condition in differential calculus?</h3>

A first-order differential equation is represented by the equation \mathbf{ \dfrac{dy}{dx} =f (x,y) }with 2 variables x & y, including its function f(x,y) specified on a xy-plane.

Given that:

\mathbf{f(x,y) =-22x^2+22xy-11y^2+110x-40y-23}

Let us first differentiate the above equation with respect to x, we have:

\mathbf{\dfrac{\partial f(x,y) }{\partial x}  = -44x +22y -0+110-0-0=0}

\mathbf{\implies  -44x +22y+110=0}        (multiply by -1)

44x - 22y = 110    ------ (equation 1)

Now, differentiating with respect to y, we have:

\mathbf{\dfrac{\partial f(x,y) }{\partial y}  =0 +22x-22y +0-40-0=0}

\mathbf{\implies 22x-22y -40=0}

22x - 22y = 40      ----- (equation 2)

Now, we have a system of equations:

44x - 22y = 110

-                      ---- ( subtracting equation 2 from 1; elimination method)

<u> 22x - 22y = 40  </u>

<u>22x    + 0  = 70    </u>

<u />

x = 70/22

Replacing the value of x into equation (1), we have:

44x - 22y = 110

44(70/22) - 22y = 110

140 - 22y = 110

140 - 110 = 22y

30 = 22y

y = 30/22

Learn more about the first-order conditions in differential calculus here;

brainly.com/question/14528981

#SPJ1

4 0
1 year ago
Find the intercept and graph the following linear equations: 2x+y=1
Dima020 [189]

Answer:

2(1)+y =1 for × intercept

2x+(1)=1 for y intercept

7 0
3 years ago
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